Y'all gonna scare the chick away

Does virtual and friend function in C++ falls under oops concept ?

Only male weebs use anime girl profile pictures online

... well sh*t..

you've been found out

... well sh*t..

Can you use ncurses with c++?

You can use any C library with C++

That means so your c++ code would be C

But please don't

You can use any C library with C++

Can you use ncurses with c++?

C++ can use any C library (and wrap it into some RAII for example if needed) the same way as Rust can use any C library and wrap into safe functions

C++ can use any C library (and wrap it into some RAII for example if needed) the same way as Rust can use any C library and wrap into safe functions

Here is a small example of C++ using ncurses https://gist.github.com/daleobrien/7535489

I thought only for C

How can I check if user input is double ?

maybe this would help: https://stackoverflow.com/questions/1681873/how-to-make-sure-input-is-a-double-in-the-c-programming-language?rq=1#:~:text=3%20Answers&text=You%20probably%20want%20a%20code,%22%25lf%22%2C%20%26number))%3B

#include <stdio.h> int main(void) { int i; { printf("How many times did you spend in bathroom: ", i); } if ( i > 0) { printf("12 * i\n"); } else { printf("You write non-positive number;"); } }

Can you help me to solve this problem, pls ! I want output, that first asks me How many times did you spend in bathroom : , and i have to write integer, if it is 0 or negative, then output have to write You write non-positive number, if it is >0, then it should multiply to 12. But my output for this code is :How many times did you spend in bathroom: You write non-positive number;

scanf is used for taking the value. In here you don't give any value to "i" hence it doesn't invoke the if statement

#include <stdio.h> int main(void) { int i; { printf("How many times did you spend in bathroom: ", i); } if ( i > 0) { printf("12 * i\n"); } else { printf("You write non-positive number;"); } }

so, what i have to do now 🤔 after first printf write scanf("%i",i); ?

A user can give a float no. Or an integer as an input so how to take the input ?

use scanf

User will give only one float or integer so how do we know ..

A user can give a float no. Or an integer as an input so how to take the input ?

It should be like this : #include <stdio.h> void main(){ int i; printf("How many times did u spend in Bathroom ? : "); scanf("%d",&i); if (i > 0 ){ printf("%d",i*12); } else{ printf("U wrote a Non-positive Number.\nPlease enter a Positive Number."); main(); } }

Wow, thank you bro my mistake with scanf, i wouldn't get it )

I highly advice that you should go through the basics of C. U lack that. It's essential to be fluent in basics.

and this quiz also for basic learners, yep ?

yeah, just search C tutorial and go through the basics

In scanf we will be mentioning both but user will input only one number so how

Example: float x; x=3.14; int y; y= (int)x; printf(“%d”, y); Output: 3

I'm just learning from CS50 Harvard courses

https://www.programiz.com/c-programming U could look at this if u want some basics on C ...

Hi! Sorry if my question is silly, but why I can't declare a const size_t value like that? int main() { const size_t n; cin >> n; {

No 1. You should initialize a const variable 2. You have to include a header that contains a definition for the type because it is not a fundamental type

I was able to run the program but not getting the output screen to run the program

Initialize choice before using it