@programminginc - страница 2602

Deleted Account

I use him to manage the reference counter.

Deleted Account

SocketServer is an intrusive ptr? Really?

socket server based intrusive ptr

Anonymous

1) Why there's even void in functions params

Deleted Account

(void) same ()

Anonymous

socket server based intrusive ptr

2) inheritance mean "is a" So with your code it's saying "socket server is an intrusive pointer" which is not true

Anonymous

(void) same ()

(void) is stupid

V01D

(void) is stupid

:0

V01D

Deleted Account

So what should I do? class NetSocketServer : public CIntrusivePtr

Anonymous

So what should I do? class NetSocketServer : public CIntrusivePtr

Learn SOLID and modern C++

Anonymous

So what should I do? class NetSocketServer : public CIntrusivePtr

This is a bad example of inheritance

Deleted Account

I use libuv, He posted a lot of asynchronous requests.

Anonymous

You should store a pointer as a member

Anonymous

Not deriving from it

Deleted Account

store a pointer as a member?

Deleted Account

If I'm storing as a member, I need very complex counter management.

Deleted Account

and close

Deleted Account

I learned SOLID.

Anonymous

Best book for learning C from beginning at home DIY

Anonymous

Best book for learning C from beginning at home DIY

DIY lol

Anonymous

If I'm storing as a member, I need very complex counter management.

Make it another class that will do this management

M.Khorram

hi any one have android developing group can i ask android related issues here ?

Hi, May I send you DM?

Deleted Account

Make it another class that will do this management

I can't do it. My reference counter is primarily a record of uv_handle_t initialization of information. If uv_write is not completed then refcnt will add 1, completion will be reduced, if all handle is turned off then it is automatically released.

Deleted Account

Do you mean ComPtr(Windows COM Interface)

Sai

#include<stdio.h> int main() { float x = 0.1; if (x == 0.1) printf("IF"); else if (x == 0.1f) printf("ELSE IF"); else printf("ELSE"); } why the output of this is ELSE IF?

Hermann

float?

Anonymous

Hi by any chance i know this sounds like a dumb question, but how could i replace user input, as he types on windows? Like if the user types a "K" somewhere i would like an "a" to appear instead. And have each character basically mapped to another character. Ive been thinking of a dumb way of doing it and just using GetAsyncKeyState(...) to check for each chatacter i want to have mapped and then simply send 2 keystokes: backspace to delete the original one and then the character i mapped it to

Anonymous

#include<stdio.h> int main() { float x = 0.1; if (x == 0.1) printf("IF"); else if (x == 0.1f) printf("ELSE IF"); else printf("ELSE"); } why the output of this is ELSE IF?

This is a percision problem. 0.1 is a double literal and you campare it to a float. If you write down 0.1 as a binary number, youll see it is a periodic number hence the percission matters

Andrew

#include<stdio.h> int main() { float x = 0.1; if (x == 0.1) printf("IF"); else if (x == 0.1f) printf("ELSE IF"); else printf("ELSE"); } why the output of this is ELSE IF?

maybe that one at the end?

Anonymous

Comparing floating points with == is always something tricky.... its in most cases a better idea to check if the number is in a specific range instead. Make sure you understand the IEEE standard for representing floating point values and how impercise they can get when using big numbers.

Andrew

Hi by any chance i know this sounds like a dumb question, but how could i replace user input, as he types on windows? Like if the user types a "K" somewhere i would like an "a" to appear instead. And have each character basically mapped to another character. Ive been thinking of a dumb way of doing it and just using GetAsyncKeyState(...) to check for each chatacter i want to have mapped and then simply send 2 keystokes: backspace to delete the original one and then the character i mapped it to

i dont know maybe editing the buffer ? like when you type the password there is a way

Renan

I tried this but can't do it pls help.reply if you guys know it.

I feel some info is lacking. 🤔

Anonymous

i dont know maybe editing the buffer ? like when you type the password there is a way

which buffer?

Andrew

every character you type in input is memorized in a buffer

Renan

I tried this but can't do it pls help.reply if you guys know it.

OK. We have 8 lines, the first two must be aligned at zero position, the next 2 zero+1, the next 2 zero+2, the next one zero+1, and the last one at zero. That is how I see it.

Anonymous

it should work cross application. Like im unlikely going to use dll injection or somwthing to get access to a buffer in another application

Renan

Nvm I missed a ; a line before

🤦‍♂️

Anonymous

OK. We have 8 lines, the first two must be aligned at zero position, the next 2 zero+1, the next 2 zero+2, the next one zero+1, and the last one at zero. That is how I see it.

Im unsure how to read files line by line again. But you can can do that and have the line as a result in char[], you can then loop over each character for a certain length and compare them to ' ' or '\t'. Meaing if the first line should be indented by 0 you check the first character only and it must me unequal to whitespace. If the 2nd line must be indented by 1 tab, the first character must be tab and the dollowing unequal to whitespace, or the first 4 character must be equal to ' ' and the following unequal to whitespace.

Andrew

it should work cross application. Like im unlikely going to use dll injection or somwthing to get access to a buffer in another application

looking around the code to make this is diffrent in linux and windows

Anonymous

? It uses the winapi

Andrew

yes

Anonymous

so not going to work on linux

Anonymous

Sry didnt understand the question or suggestion?

Renan