@programminginc - страница 2561 - Telegram web archive

@programminginc 2561

数学の恋人

that was one rude fellow sharing fake US bank accounts

klimi

that was one rude fellow sharing fake US bank accounts

Indeed

klimi

Ah damn he came into offtopic

Vlad

that was one rude fellow sharing fake US bank accounts

Very scummy indeed

Anonymous

.

kartik

Hi

kartik

Need help sublime TXT 3 my code output terminal not prompt

kartik

Anyone who help

kartik

New to coding

kartik

Any help

Andrew

Sublime is not very good

SK

Do anyone have experience with python

Anonymous

Do anyone have experience with python

/warn offtop

Nazarova Muslibar

Do anyone have experience with python

#offtopic

Anonymous

What is that? I just sent link to the group rules!

Vlad

Nice virus. Approve 👍

Anonymous

The rules say not to post executables

Vlad

So you've decided to share your virus collection with us?

Vlad

I loaded up previous one in VM and my PC exploded

Nazarova Muslibar

So you've decided to share your virus collection with us?

😁

Anonymous

The rules say not to post executables

The rules say not to post executables * 2

Nazarova Muslibar

The rules say not to post executables

Ok I'm sorry

Nazarova Muslibar

Roxifλsz 🇱🇹

/warn someone needs to learn to read

Anonymous

What is that? I just sent link to the group rules!

@roxifas ?

Dima

Removed

Anonymous

Arkadaşlar bana sağlam bilgisayar önerebilir misin? Yazılım ve grafik için.

Anonymous

Need help sublime TXT 3 my code output terminal not prompt

You can choose VS code

Phil

/get cbook

Roxifλsz 🇱🇹

Arkadaşlar bana sağlam bilgisayar önerebilir misin? Yazılım ve grafik için.

/warn this isn't a Turkish chat

Anonymous

/warn this isn't a Turkish chat

Noluyor?

Vlad

Read the rules. It is English only.

Anonymous

Sorry ok.

Brown

Why char *a = "some string"; is read only ? And why this doesn't work for array of ints ?

Vlad

Why char *a = "some string"; is read only ? And why this doesn't work for array of ints ?

'Cause const char* literal

Ammar

Why char *a = "some string"; is read only ? And why this doesn't work for array of ints ?

This can be legal if you cast it to (char *).

Ammar

char *a = (char *)"some string";

Vlad

This can be legal if you cast it to (char *).

No it's not

Brown

char *a = (char *)"some string";

Then I can change ?

Ammar

I often do that.

Vlad

I often do that.

And then write to that string?

V01D

Since we are talking about strings - which is safer (kernel wise): char str[100] = "String"; or char* str2 = "String2"; ?

Vlad

Since we are talking about strings - which is safer (kernel wise): char str[100] = "String"; or char* str2 = "String2"; ?

str2[0] = 'a' is UB

Vlad

You can't write into it

Ammar

Then I can change ?

Oh no.

Ammar

And then write to that string?

That is still readonly.

Ammar

Sorry, I didn't read the question carefully.

Vlad

That is still readonly.

Then why cast to char* tho?

Vlad

Leave it const char*

Ammar

Then why cast to char* tho?

Just to get rid compiler warning.

V01D

You can't write into it

Strings are immutable, I know. I meant which string implementation is safer

Brown

Okay, why doesn't this work for int of others?

Vlad

Just to get rid compiler warning.

I mean why this char* a = (char*)"asdf"; instead of this? const char* a = "asdf"

Brown

Array of ints, I mean. Int *p = {1,6,5}

Anonymous

Array of ints, I mean. Int *p = {1,6,5}

{1, 6, 5} is not an array of ints

Vlad

I mean why this char* a = (char*)"asdf"; instead of this? const char* a = "asdf"

And you won't accidentally write to the second one either.

Vlad

Array of ints, I mean. Int *p = {1,6,5}

int arr[] = {1, 6, 5}; You meant

Anonymous

{1, 6, 5} is not an array of ints

if you are using C++, this is an std::initializer_list<int>

Anonymous

int arr[] = {1, 6, 5}; You meant

that's just invalid syntax

Ammar

I mean why this char* a = (char*)"asdf"; instead of this? const char* a = "asdf"

Because I sometimes I have to assign "xxx" to char *. I may violate some best practice for that.

Vlad

Because I sometimes I have to assign "xxx" to char *. I may violate some best practice for that.

Ammar

As I remember, first time I saw the xdebug source code like that and it became my habit.

Anonymous

+1

Anonymous

As I remember, first time I saw the xdebug source code like that and it became my habit.

writing invalid programs is not a good habit

Vlad

that's just invalid syntax

https://godbolt.org/z/8fP7bT

Vlad

It's as valid as it gets :P

Anonymous

https://godbolt.org/z/8fP7bT

oh right

Vlad

Even more so in C89 it was the only way to init char arrays

Anonymous

sorry

Brown

int arr[] = {1, 6, 5}; You meant

Yes but, if char *p = "something" I thought why not int *p = {1,24,7} since in both case p has given an address.

Vlad

Yes but, if char *p = "something" I thought why not int *p = {1,24,7} since in both case p has given an address.

Second one is not valid

Ammar

writing invalid programs is not a good habit

Yeah, I am going to fix that habit.

Ammar

https://github.com/xdebug/xdebug/blob/78d25b202981376e1f343132299d79517888cfaf/xdebug.c#L517-L524

Ammar

That is what I meant.

Anonymous

Because I sometimes I have to assign "xxx" to char *. I may violate some best practice for that.

Lol Do you like writing error-prone code? char* str = (char*)"Hello, UB"; str[0] = 'F'; // oops, UB

Ammar

https://github.com/xdebug/xdebug/blob/78d25b202981376e1f343132299d79517888cfaf/xdebug.c#L517-L524

ZEND_STRL("_ENV") will expand to "_END", sizeof("_ENV") - 1

Vlad

Lol Do you like writing error-prone code? char* str = (char*)"Hello, UB"; str[0] = 'F'; // oops, UB

++

Brown

Second one is not valid

Why doesn't it work ?

Vlad

Why doesn't it work ?

Cause pointers are not arrays

Anonymous

Even more so in C89 it was the only way to init char arrays

yeye the pointer one was invalid syntax because {1, 6, 5} was not an array of ints. but the [] is correct syntax because each element of the array is initialised using the braced list.

@programminginc 2561