Using vectors, is there a way to erase the object that calls is without passing the whole vector?

Using vectors, is there a way to erase the object that calls is without passing the whole vector?

Use ref?

For example classname::destroy() { vector.erase(); }

Let me explain better: I have a method (Ship::destroy()) that will be called from different functions and needs to esare an element of a vector when called. I thought of doing something like void Ship::destroy(std::vector<Ship>& vector, int index) { vector.erase(index); } but is there a way to do it without having to pass both the vector and the index to the function?

Let me explain better: I have a method (Ship::destroy()) that will be called from different functions and needs to esare an element of a vector when called. I thought of doing something like void Ship::destroy(std::vector<Ship>& vector, int index) { vector.erase(index); } but is there a way to do it without having to pass both the vector and the index to the function?

so the ship is a vector because there could be more of them (it's not the level, is a character), everytime I call the destroy method I want that element to be removed from the vector and disappear. the vector is declared in the main, but each element is deleted individually from a class method, not from the main

Looks like your architecture is a bit of a mess :P

what could be a better way to make characters?

Hey plebes

>plebes Hey buddy, I think you've got the wrong door, the leather club's two blocks down.

Can anyone please explain me what >>= mean in b >>=1

Can anyone please explain me what >>= mean in b >>=1

Same as b /= 2

If we can do like this b / = 2 Why there is b >>=1 In language

Also without optimization /= 2 could be an actual division instead of faster bit shifting

Mean bitwise operation are considered fast in practice ?

They are quite fast.

@roxifas ( ͡° ͜ʖ ͡°)

Don't worry about interviews, worry about how you actually program.

struct N { constexpr N() {} N(N const&) = delete; }; template <typename T> consteval void assert_copyable() { T t; T t2 = t; } using check = decltype(assert_copyable<N>());

Ill-formed just because it's ugly and hard to understand.

struct N { constexpr N() {} N(N const&) = delete; }; template <typename T> consteval void assert_copyable() { T t; T t2 = t; } using check = decltype(assert_copyable<N>());

Ill-formed just because it's ugly and hard to understand.

+

can std::vector erase() delete the last element of a vector?

Stuff like this is exactly why I use C++ just as C with classes

cppreference.com Checkout the docs before asking a question

It's too boring

If you're looking for """"fun"""" in code, sure, but I just want my code to work and also not be an unreadable plate of spaghetti

I will change my question in: i there a reason why a std::vector erase() would work with one class and not the other?

*javascript and python are looking thru the dark room*

Shut up, do not remind me of those cursed hellscapes

I have one vector made of 1 item and another vector made of 20 items, vector.erase(vector.begin() + index) works fine on the vector made of 20 items but not on the vector made of 1 item