node p1 = new node; // This throws error. Why?

Yeah exactly why that pointer thing works? Not not a normal datatype?

because "the result of the new-expression is a pointer to the object created."

#include <iostream> using namespace std; struct Node { int d3 = 13; }; int main() { Node* p1 = new Node; *p1->d3; return 0; } // This throws an error. How do you print the value of d3? Using p1 object?

https://en.cppreference.com/w/cpp/language/pointer It doesn't throw an error, it fails to compile because the syntax is invalid

What would be the valid syntax then?

the page I linked has an example

#include <iostream> using namespace std; struct Node { int d3 = 13; }; int main() { Node* p1 = new Node; *p1->d3; return 0; } // This throws an error. How do you print the value of d3? Using p1 object?

#include <iostream> using namespace std; struct Node{ int d3 = 13; } p1; int main(){ Node *p1 = new Node(); p1->d3; return 0; }

Why the brackets after Node? On the line after int main()

Okay

👍👍

Okay

Why don't you use class? For example:

Actually I am learning to implement a linked list. In the tutorial they use both class and struct. So therefore I'll have to learn both.

Ok. Thanks

No problem dude. You're a legend.

Anyone have a python discussion group on telegram??????? If yes then pls let me know..

Use the telegram search

struct Node {}; int main() { Node *p1; Node *p2 = new *p2; } // What is the difference between *p1 and *p2? (They are different because while creating *p1 the constructor doesn't gets called. I have tried it.) So what's happening?

And difference between (1) Node *p2; And (2) Node *p2 = new Node; Is in 1st it is pointer to node you can not store any new value in it. So by this you can point existing node In 2nd case there new memory will be allocated for value you want to store.

What's the best way to throw exception (I don't have to catch it)

best is kinda vague and broad term here, What I really mean is what is good practice to throw exception

-fno-exceptions :)

to pass function as argument for example

aah, so instead of passing the return of a function, i can pass the function itself and call it within another function?

for example you have traverse function, and for each node needs to call a function. so you pass pointer to specific function as argument. for example you have some event and need to call some a function, so you pass pointer to specific function as argument in event handling engine

i still cant find a solution for this

why the standard library doesn't has such a construct: to make the compiler decide whether to pass by value or reference instead of just passing by const T& because we don't know what the user will pass template<typename, bool> struct OptimizedType; template<typename T> struct OptimizedType<T, true> { using type = const T&; }; template<typename T> struct OptimizedType<T, false> { using type = T; }; template<typename T> using OptTypeT = typename OptimizedType<T, (sizeof(T) > 8)>::type; then the user will just define his function like this template<typename T> void test(OptTypeT<T> value){}

to pass function as argument for example

what shall i use then

wouldn't functors come in useful there?

ok

why the standard library doesn't has such a construct: to make the compiler decide whether to pass by value or reference instead of just passing by const T& because we don't know what the user will pass template<typename, bool> struct OptimizedType; template<typename T> struct OptimizedType<T, true> { using type = const T&; }; template<typename T> struct OptimizedType<T, false> { using type = T; }; template<typename T> using OptTypeT = typename OptimizedType<T, (sizeof(T) > 8)>::type; then the user will just define his function like this template<typename T> void test(OptTypeT<T> value){}

fseek(fp, 0, SEEK_END); if(feof(fp)) printf("END"); Why doesn't feof return true? It does if I read a character using getc(fp) before the if condition. fp is a pointer to a file opened in read mode.

i still cant find a solution for this