behavior of the function will be the same. its just to supress compiler warning

?

check all pointers for NULL

also I don`t know about comment function

and this one int array = sizeof(line); fseek(opf, -array, SEEK_CUR); is weird

also I don`t know about comment function

My program open a pnm file which contain a matrix it scann the matrix but before scanning the matrix there is a comment line which begin with #, remove comment detect that and comment() remove it

25

How you solve it because i got another answer

How you solve it because i got another answer

Dm me the question again and i will show u

It's working perfectly

Oh wow, I didn't even test it before suggesting it. 😅

@PO_uria by the way... Why not just get the file format that the user wants from the filename?

Here's the question: codechef(dot)com/problems/HORSES And here's my code: #include <stdio.h> #include <stdlib.h> int main(void) { int i, t, n,res; scanf("%d",&t); for(i = 0; i < t; i++){ scanf("%d",&n); res = diff(n); printf("%d\n",res); } return 0; } int diff(int num){ int arr[num]; int i, min = 1000000001, j, k; for(i = 0; i < num; i++){ scanf("%d",&arr[i]); } for(i = 0; i < num; i++){ for(j = 0; j < num; j++){ k = abs(arr[j] - arr[i]); if(k < min && k != 0) min = k; } } return min; } I'm getting the correct outputs when I run with custom inputs. Can someone tell me where I'm wrong? I know this is an easy question and most of you here are pros, but any help is appreciated. Thank you.

@shshshhsll Just guessing. But it seems you are avoiding comparing the same horse by testing if k!=0 (since the same horse gives the same value)

But it is possible for k to be 0 in other conditions (ex: different horses have the same value)

@PO_uria by the way... Why not just get the file format that the user wants from the filename?

Because, it doesn't ask me like that and the file is a matrix file (pnm) so it doesn't work if the format of the file and the format which user has entred don't match

I want to learn strings

#include <stdio.h> int main() { int x = 45; if( x > 95) { printf( "Student is brilliant\n"); } if( x < 30) { printf( "Student is poor\n"); } if( x < 95 && x > 30 ) { printf( "Student is average\n"); } }

#include <stdio.h> int main() { int x = 45; if( x > 95) { printf( "Student is brilliant\n"); } if( x < 30) { printf( "Student is poor\n"); } if( x < 95 && x > 30 ) { printf( "Student is average\n"); } }

it seems to me it will print nothing for 30 and 95

it seems to me it will print nothing for 30 and 95

🤷🏽‍♂🤷🏽‍♂

Not warning you for the sticker this time.. but don't post such stuff

Not warning you for the sticker this time.. but don't post such stuff

can u refer me to C++ related stickers

thank you sir.

You can share normal stickers

That one was kinda nsfw

Lol

Is this ok?

can u refer me to C++ related stickers

Thank you Mr frog sir

Is this ok?

Yea 😂

How to call the print() function of the class A from the object of class D in this Hybrid inheritance

How to call the print() function of the class A from the object of class D in this Hybrid inheritance anybody please

d.A::print()

Oh it would be ambiguous I assume

Yes

One can do static_cast<B&>(d).A::print()

One can do static_cast<B&>(d).A::print()

It worked but why ??? Could you please elaborate this

It is a cast to subobject b of object d. b has unambiguous (one) base A

It is a cast to subobject b of object d. b has unambiguous (one) base A

thanks 👍

Is it necessary to have deep knowledge of os for being a protocol developer?

Hi

Hi

Hi?

🤪

Hi?

Hi?

Hi?

Hi?

Hi?

Hey sergey, long time no see! still developing?

Hey sergey, long time no see! still developing?

At this time - no. Probably will in future.

Hi there !

@GitGpAdmin

Admin

Need data structures pdf latest version

Hi, is there any number type that somehow, magically, can hold as big numbers as the memory allows?

Hi, is there any number type that somehow, magically, can hold as big numbers as the memory allows?

You have to use GMP or some multiprecision library. There's nothing lika big int in the standard

You have to use GMP or some multiprecision library. There's nothing lika big int in the standard

Thx

/get

Hi

I Am New friends

Hey New

Hey New

Hey Dima

Yes

Can anyone explain to me what is happening in this code?

https://pastebin.com/9A0QN48L

Most importantly how can we pass it as "vec2" on line 10? It should be something like &vec2 right? How is it still working?

https://pastebin.com/9A0QN48L

vec2 and vec1 have the same type

Hello. size_t func(size_t num) { return num; } int main() { size_t k = 2; size_t n = func(k); std::cout « n « std::endl; }

Why n print to me like 0?

https://pastebin.com/3Y4sFFGy When enter to if (current_sum == sol_number) and sol_size is different to 0 in ligne 6 print ZERO

/* * In this example, we design an algorithm that calculates the monthly paycheck of a salesperson * at a local department store. * Every salesperson has a base salary. * The salesperson also receives a bonus at the end of each month, based on the following criteria: * If the salesperson has been with the store for five years or less, * the bonus is $10 for each year that he or she has worked there. * If the salesperson has been with the store for more than five years, * the bonus is $20 for each year that he or she has worked there. * The salesperson can earn an additional bonus as follows: * If the total sales made by the salesperson for the month are at least $5,000 * but less than $10,000, he or she receives a 3% commission on the sale. * If the total sales made by the salesperson for the month are at least $10,000, * he or she receives a 6% commission on the sale. */ #include <iostream> using namespace std; int main() { cout << "******************************************\n"; cout << "***EMPLOYEE'S MONTHLY SALARY CALCULATOR***\n"; cout << "******************************************\n"; string name; int years; double sales; double baseSalary; int bonus; int commission; if(years <= 5) bonus = 10 * years; else bonus = 20 * years; if(sales < 5000) commission = 0; else if(sales >= 5000 && sales < 10000) commission = 0.03 * sales; else commission = 0.06 * sales; int maxSalary = baseSalary + bonus + commission; cout << "Name: "; cin >> name; cout << "Working Period (Years): "; cin >> years; cout << "Sales: $"; cin >> sales; cout << "Base Salary: $"; cin >> baseSalary; cout << "Salary: $" << maxSalary; return 0; }

Can anyone help me to figure out what is wrong with the code?

After compiling, I get Salary as 0.

I kept on staring and I just realized it was all my arrangement of the inputs. Fixed it. Thanks.

Hello, how can I ensure a copy constructor copies into a blank object rather than an already instantiated one? It is causing a really nasty bug for me previously gone unnoticed

Hello, how can I ensure a copy constructor copies into a blank object rather than an already instantiated one? It is causing a really nasty bug for me previously gone unnoticed

Copy constructor always copy to object pointed by this pointer. Check what object this pointer is pointing to...

I know what object it's pointing to, and it's not blank

In the error, *this is a pointer inside my &obj, which is causing a recursive issue

generally I watch the copy constructor copy into a blank *this

Are you passing the object by reference inside copy constructor?

and for the first hit in a particular function it is blank... but the second time it's not

generally I watch the copy constructor copy into a blank *this

It depends on which object we are calling copy constructor