take two strings, take their length (strlen), allocate a new one and send characters

this

same issue with ON_CALL as well.

take two strings, take their length (strlen), allocate a new one and send characters

Do we have to allocate ? Any other way ?

Hi.. can anyone explain me the logic for this code ? "To combine two Strings without using strcat() in c "

You can't exactly

It depends on the binding

Binding ?

For instance let's say char a[100] = "string" char b[100]= "str2"

You can use ptr=a[strlen(a)] strcpy(ptr,b);

For instance let's say char a[100] = "string" char b[100]= "str2"

100 for ‘string’ gg

But now

Hi.. can anyone explain me the logic for this code ? "To combine two Strings without using strcat() in c "

See first calculate the lenght of str1 until \0 using while loop then using while loop str1[i]=str2[j] I++ and j++ then put \0 at last of str1 print str 1 Done

For instance let's say char* a= "string" char* b= "str2"

This is const

Also you can literally just

printf("%s%s",str1,str2);

printf("%s%s",str1,str2);

See? Very easy

Now you want to, say

Concatenate 2 strings

See? Very easy

Yea..lil confused..

char *concat(char *str1, char* str2) { char *ret = malloc(1+strlen(str1)+strlen(str2)); for(unsigned long i = 0; i<strlen(str1);++i) ret[i]=str1[i]; for(i=0; i<strlen(str2);++i) ret[i+strlen(str1)] = str2[i]; ret[strlen(str1)+strlen(str2)] = 0; return ret; }

char *concat(char *str1, char* str2) { char *ret = malloc(1+strlen(str1)+strlen(str2)); for(unsigned long i = 0; i<strlen(str1);++i) ret[i]=str1[i]; for(i=0; i<strlen(str2);++i) ret[i+strlen(str1)] = str2[i]; ret[strlen(str1)+strlen(str2)] = 0; return ret; }

Thanks

char *concat(char *str1, char* str2) { char *ret = malloc(1+strlen(str1)+strlen(str2)); for(unsigned long i = 0; i<strlen(str1);++i) ret[i]=str1[i]; for(i=0; i<strlen(str2);++i) ret[i+strlen(str1)] = str2[i]; ret[strlen(str1)+strlen(str2)] = 0; return ret; }

See first calculate the lenght of str1 until \0 using while loop then using while loop str1[i]=str2[j] I++ and j++ then put \0 at last of str1 print str 1 Done

Mine is better 😜

Oh you mean to say that strcat() follow the same procedure he described.

But mine was easy to understand for beginner 😔

Yes 🤧

But mine was easy to understand for beginner 😔

Yea..thanks buddy 😁

Test runs fine with a raw pointer but I am not getting why this happens

😐😩

Yea..thanks buddy 😁

😁😉 you know much more than me I am bigginer

char *concat(char *str1, char* str2) { char *ret = malloc(1+strlen(str1)+strlen(str2)); for(unsigned long i = 0; i<strlen(str1);++i) ret[i]=str1[i]; for(i=0; i<strlen(str2);++i) ret[i+strlen(str1)] = str2[i]; ret[strlen(str1)+strlen(str2)] = 0; return ret; }

Finally I got it. Nice code 👍

Finally I got it. Nice code 👍

Just read any book on any ISA

This is almost a standard string concatenation algorithm

I merely translated it to C from the assembly equivalent

I'm not bro 😂

one more time and you’ll get warn or ban

Identify the gender first 🙂

one more time and you’ll get warn or ban

Yes maam

BTW @Ritik_Tiwari you can optimize it further

Observe how I'm not modifying str1 and str2

You can make them const

And you can make variables to hold strlen() calls instead of calling the function every time

I never assume the compiler and GCC and clang both behave very differently at -O3

Alright

Hello

Hello everyone, I'm trying to do a while where I make a sequence of 1 and 0 walk inside the positions. For example, a sequence of 5 positions starting from 0 to 4 would look like this: 11010 01101 10110 01011 10101 11010 / this last one does not need to be repeated since it is equal to zero

a bug on windows

offset = 0; while (offset <= mmc){ a = 0; b = 0; int maior[mmc]; memset(maior, 0, mmc*sizeof(int)); while (a < mmc/pattern->v) { for (c=0; c < pattern2->k; c++){ maior[((pattern2->onSlots[c] + a*pattern2->v) % mmc) + mmc % offset] = 1; printf("offset %d", offset); printf("maior %d-> %d\n",b, maior[b]); b++; } a++; } for (k=0; k < mmc; k++){ if ((menor[k] == 1) && (maior[k]==1)){ //printf("ACHOU em %d, menor %d, maior %d\n",k, menor[k], maior[k]); } } offset++; }

however if I use mmc% offset it gives an error execution of the floating point image of the recorded core. if i use offset% mmc it does not return 1 in position 0 and so on. could someone help me?

Hello everyone, I'm trying to do a while where I make a sequence of 1 and 0 walk inside the positions. For example, a sequence of 5 positions starting from 0 to 4 would look like this: 11010 01101 10110 01011 10101 11010 / this last one does not need to be repeated since it is equal to zero

Ah you're trying to implement rotate in C

https://www.geeksforgeeks.org/rotate-bits-of-an-integer/

Ah you're trying to implement rotate in C

yes

I believe that I cannot use this function because there is a check in each position

Wht's this

Is sizeof operator compile time operator or run time operator?

Is sizeof operator compile time operator or run time operator?

It's a compile time

It's a compile time

what if len of array uknown, how do compiler know sizeof array

Guys i need help

I have tried saving/ run my first hello program in windows os with .cc but it cant run as program pls what should u do?

what if len of array uknown, how do compiler know sizeof array

Hmm yeah Looks like sizeof performs mostly compile-time computations when it's possible I just tried it

Hmm yeah Looks like sizeof performs mostly compile-time computations when it's possible I just tried it

Never thought of it till this moment

Never thought of it till this moment

Okay thanks for that answer

Okay thanks for that answer

You are welcome

Okay thanks for that answer

I edited

I edited

so sometimes it calculated run time, am i wrong?

so sometimes it calculated run time, am i wrong?

Yeah

okay thanks again

Please note that C++ ISO forbids variable array length

Yeah

I guess we're talking about sizeof applied to a variable and not a type, am I right? And btw, in which cases does it evaluate at run-time?

I guess we're talking about sizeof applied to a variable and not a type, am I right? And btw, in which cases does it evaluate at run-time?

if array lenght is a variable, sizeof calculated runtime

if array lenght is a variable, sizeof calculated runtime

But in C++ there's not such thing as "variable length array", and that's why I'm asking

But in C++ there's not such thing as "variable length array", and that's why I'm asking

actually i asked for C language

actually i asked for C language

You actually didn't, so this is new information for me

In C may be okay, in C++ I can't think of example for that

Need help guys

I have tried saving/ run my first hello program in windows os with .cc but it cant run as program pls what should u do?

You need to compile it first

In C may be okay, in C++ I can't think of example for that

#include <iostream> int main(){ int n = 5; int arr[n]; arr[0] = 1; std::cout << arr[0]; } In c++ with g++ i can compile that source code, how ?

You need to compile it first

Please how to do this