Google what smart pointers are

you look like a googleman

Google your momma

What are you trying to achieve in first place? This code smells

Google what smart pointers are

Or you can just read it in Modern Effective C++ by Mayers

Anyway can you help in answering those?

You need to correct all your mistakes

struct X{ map<int,X*> mp; }; void fun(X* root){ root->mp[6] = new X; } int main(){ X *root = new X; fun(root); } 1. Wanted to ensure that, on the call of fun(X* root), root->mp[6] resides in heap and the newly created X is also in heap. So, a pointer in heap points to something on heap. 2. Does delete(root->mp[6]) deletes the the newly created object?

Yes

did i really see 'use c#' as a response to smart pointers

rude.

?

You question was will it be deleted - yes it will. Or did I miss something?

struct X{ map<int,X*> mp; }; void fun(X* root){ root->mp[6] = new X; } int main(){ X *root = new X; fun(root); } 1. Wanted to ensure that, on the call of fun(X* root), root->mp[6] resides in heap and the newly created X is also in heap. So, a pointer in heap points to something on heap. 2. Does delete(root->mp[6]) deletes the the newly created object?

everything created with new is on the heap

The object is on heap and so is the object to which it's member mp is pointing to. Right?

whether the pointer is on heap or not depends on the map implementation. in STL I'm pretty sure it's on heap, but some custom map can theoretically have some buffer (judy array) with small buffer optimization then it can be on stack. but thats super unlikely. never heard of such implementations of map

Even if that happens in some implementation but can it happen that an object exists in heap and its member on stack. If yes, can you give an example?

whether the pointer is on heap or not depends on the map implementation. in STL I'm pretty sure it's on heap, but some custom map can theoretically have some buffer (judy array) with small buffer optimization then it can be on stack. but thats super unlikely. never heard of such implementations of map

they can't go to stack

Assuming that map exists on heap so what I said is correct. Right? or I'm wrong somewhere

yes, its correct

If I want to create a Matrix array during the run time. One way is this: class matrix{ int **p; int d1, d2; public: matrix(int x, int y); void get_element(int i, int j, int value){ p[i][j]=value; } int &put_element(int i,int j) { return p[i][j]; } }; matrix::matrix(int x, int y){ d1 = x; d2 = y; p = new int *[d1]; for(int i = 0; i < d1; i++) p[i] = new int[d2]; } Are there any option

Help

Hi

what to do if it says: "DWORD Hackprocess::GetModuleNamePointer(LPSTR,DWORD)": it is impossible to convert argument 1 from "const char (11)" in "LPSTR"

got addicted to that convention after looking at UE4’s code

What do the [] brackets mean here, seeing as they are at the beginning of assignment?

is it C++?

is it C++?

But yeah, it doesn't seem like C++

It's located in a .mm file, and from what I understand that indicates C++ for an Objective C compiler

objective C/C++ is not C++ square braces mean method call in objective C as far as I remember

How to store a 16 bit integer in cpp ????

int16_t

How to store a 16 bit integer in cpp ????

Is it an alias for unsigned short?

Is it an alias for unsigned short?

unspecified = implementation defined

Sorry I didn't get you

Sorry I didn't get you

Is it an alias for unsigned short?