Who can help me? There were ten errors in the pseudocode,and I can’t find all of them.

how do u known are 10?

how do u known are 10?

The professor said.

hi all

just wondering on C i'm very new at it but how would i print the output of system()?

Hello developer and student What is your average age and education

just wondering on C i'm very new at it but how would i print the output of system()?

popen

popen

thanks

/saved

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Oh, darn it, I missed the person to contact from that scam, I wanted to troll the scammer like I am trolling one right now.

If I use sizeof(function) does it return the size of the function's return type or something else?

If I use sizeof(function) does it return the size of the function's return type or something else?

It returns size of function pointer

Damn. Is there anyway to get the size of its return type?

Damn. Is there anyway to get the size of its return type?

You need to "call" function

Damn. Is there anyway to get the size of its return type?

sizeof(fun(0, 0, 0, ...))

sizeof(func(...))

And that's completely static?

I suppose it makes sense that you have to provide parameters due to overloading

And that's completely static?

What do you mean by static?

And that's completely static?

yes. sizeof is totally compile time; except for variably modified types

yes. sizeof is totally compile time; except for variably modified types

What are "variably modified types"?

What are "variably modified types"?

type of a variable length array

type of a variable length array

It's illegal in C++ though

I suppose it makes sense that you have to provide parameters due to overloading

It makes sense where there's no overloading either sizeof calculates expression type and then calculates it's size

Expression type of just function name is pointer to the function

Hi all

hi

Hi all

Nohello.com

I'm having to use a C++ version below 14, so I can't use auto in a lambda parameter. How do I write const lambda []void (uint8_t*, uint8_t)->void as a parameter type?

I'm having to use a C++ version below 14, so I can't use auto in a lambda parameter. How do I write const lambda []void (uint8_t*, uint8_t)->void as a parameter type?

To clarify, I'm passing a lambda to a lambda

I'm having to use a C++ version below 14, so I can't use auto in a lambda parameter. How do I write const lambda []void (uint8_t*, uint8_t)->void as a parameter type?

No way

Lambdas types are not exposed to programmer

And every lambda has its own unique type

But there's some possibility

There are two, actually

1) Your function parameter is function pointer with signature you need. But you cannot pass lambdas with captures

1) Your function parameter is function pointer with signature you need. But you cannot pass lambdas with captures

While VSC thinks it's correct syntax GCC doesn't compile it (thus far when I try it)

2) Your function parameter is std::function with signature you need. You can pass lambdas with captures but it has a little overhead

While VSC thinks it's correct syntax GCC doesn't compile it (thus far when I try it)

Give the code via godbolt.com with your compiler version

that'll be a little difficult, but I'll try make a minimal version of it

It is correct syntax since by C++ standard lambdas with no capture can be implicitly casted to function pointer

it's a closure

auto appender = [&] (const char* path) { return [&h, path] (uint8_t* data, uint8_t len) -> void { h->fileAppend(path, data, len); }; }; const auto binOut = appender("entry.bin"); It's small. Just later passing binOut to another lambda.

it's a closure

Well, you cannot pass closures as function pointers

So the only way is to use std::function

Gahhh, that sucks

I can't afford the overhead so I'll probably have to use a global

std::function<void(uint8_t*, unit8_t)>

I can't afford the overhead so I'll probably have to use a global

Why is that?

it's for Arduino

I'm being cheeky as it is using closures

Arduino has no C++14 support?

It will vary between board architecture

Can clang compile to Arduino?

Not sure about that. Regardless though, I'm trying to provide frictionless compilation with just the Arduino IDE so I've got to stay rather compatible

Meh

I could just tweak the platform spec and see what happens but I can't ask end users to do that 😅

Do not use globals

Implement your functionality with classes

Do not use globals

Arduiono can be considered embedded, so globals are way to go

I didn't quite mean global, as it's all within one method already

Ofc only when its very hard/inconvenient to do it other way

so, a local they both the caller and callee are within scope of

but now I'm not sure what type to give the local 😂

I should probablyyyyy go about this without any lambda, unfortunately

Any books and tutorials on socket programming in c/c++, (already searched on Google, only found example programs). Thanks in advance

man select

Please Any books and tutorials on socket programming in c/c++, (already searched on Google, only found example programs). Thanks in advance.

Please Any books and tutorials on socket programming in c/c++, (already searched on Google, only found example programs). Thanks in advance.

https://beej.us/guide/bgnet/

https://beej.us/guide/bgnet/

Thank you so much

Oh, darn it, I missed the person to contact from that scam, I wanted to troll the scammer like I am trolling one right now.

lol

Oh, darn it, I missed the person to contact from that scam, I wanted to troll the scammer like I am trolling one right now.

you will get limited very soon

you will get limited very soon

I am limited to chu uwu

you will get limited very soon

?

I couldn't understand what you meant by that.

lol