@programminginc - страница 2198

Jaaziel

Ansya

As I understand, Visual code is an editor and need compiler for that reason. Offering many addons, for each lenguage and more. An IDLE so, is? Editor and compiler in one?

Eclipse, love it :)

Anonymous

As IDE I only liked Netbeans so far

Ansya

Like as jetbrains

Anonymous

C-Lion? He is good for personal use?

Anonymous

I think it's not a good idea, pay to a IDE, only for personal use!

Dima

C-Lion? He is good for personal use?

use EAP, it’s free

Anonymous

use EAP, it’s free

Yeah

Anonymous

It better

Sasuke

Why I can't do this; int *intPtr = &5; Where I can do this const char *stringPtr = "Hi, There";

Chernykh

U can't get the ptr from rvalue

Sasuke

Isn't both are literals?

I_Interface

Isn't both are literals?

Read about rvalue, references and pointers.

Anonymous

You be putting the 5 address in intPtr pointer? Wtf

Anonymous

I_Interface

Why I can't do this; int *intPtr = &5; Where I can do this const char *stringPtr = "Hi, There";

U can do: int* intPtr = new int(5);

Sasuke

You be putting the 5 address in intPtr pointer? Wtf

Why 5 doesn't have a memory location?

I_Interface

Why 5 doesn't have a memory location?

Because it isn't a variable ?

Anonymous

Why 5 doesn't have a memory location?

It is a value, not a variable

Sasuke

Because it isn't a variable ?

So does "Hi, there"

Anonymous

The 5 address it is protected by the protected mode.

I_Interface

So does "Hi, there"

It is the const char array.

Anonymous

IA-32

I_Interface

The 5 address it is protected by the protected mode.

Nah, it's too hard for him).

Sasuke

The 5 address it is protected by the protected mode.

Do u mean read-only location?

Anonymous

Ye

Anonymous

You not can access

I_Interface

You not can access

can not*

Anonymous

Thx

Sasuke

It is the const char array.

I can make a array of that those characters bcz I have location of them right?

I_Interface

I can make a array of that those characters bcz I have location of them right?

u have a pointer to array and can read it easy.

Sasuke

u have a pointer to array and can read it easy.

No you didn't get me

Sasuke

u have a pointer to array and can read it easy.

I can create a const array(which is basically a pointer to first element) with string literal but can't get the address of integer literal why?

Anonymous

I think it's works: int *intptr = 0x637c52; But this could be a Segmentation Fault, or General Protect Fault, I don't try it! If you can't access this address directly.

Anonymous

I can create a const array(which is basically a pointer to first element) with string literal but can't get the address of integer literal why?

use this: int *p = (int[]){ 5 };

Sasuke

use this: int *p = (int[]){ 5 };

I don't want a fix I wanna know why this certain behaviour

Anonymous

I don't want a fix I wanna know why this certain behaviour

integer constant have no address. enum { X = 5 }; int *p = &X; that's because of compiler optimization. that constant might be a feature of a machine instruction. for example: a = 5 * b; might be translated to: lea eax, [4 * ecx + ecx]

Sasuke

integer constant have no address. enum { X = 5 }; int *p = &X; that's because of compiler optimization. that constant might be a feature of a machine instruction. for example: a = 5 * b; might be translated to: lea eax, [4 * ecx + ecx]

And string literals have addresses?

Anonymous

And string literals have addresses?

Sure

Sasuke

Sure

Why? Integral literals don't have!

Anonymous

And string literals have addresses?

string literal are equivalent to arrays. these two are equivalent: "Hello World!" (char []){ "Hello World!" }