d[i] == 0

Use --t

d[i] == 0

#include <bits/stdc++.h> using namespace std; int main() { // your code goes here unsigned short int t; cin>>t; while(t--){ unsigned short int n; unsigned long int p; cin>>n>>p; unsigned long int d[n]; for(unsigned short int i=0;i<n;i++) cin>>d[i]; bool flag=true; for(unsigned short int i=n-1;i>=0;i--) { if(p%d[i]!=0) {flag=false; int x=p/d[i]; d[i]=x; p-=d[i]*x; } else d[i]=0; } if(flag) cout<<"YES"; else cout<<"NO"; for(unsigned short int i=0;i<n;i++) cout<<" "<<d[i]; cout<<endl; } return 0; }

https://www.simplilearn.com/skills-required-to-become-a-full-stack-developer-article

https://www.simplilearn.com/skills-required-to-become-a-full-stack-developer-article

when u r using negation we have to use single sign only

So?

yeah thats the standard way

Or is it all?

Sometimes I see questions like that I think "r u banned in debuger"?

Or I didn't understand you, or you didn't explain, why d[i] can't be 0

d[i] can be zero but for equality comparison if(d[i]!=0) correct only. in case u r getting confused

Then how do u want to calculate p%d[i] != 0?

Wait until i'll drink pls

Then how do u want to calculate p%d[i] != 0?

#include <bits/stdc++.h> using namespace std; int main() { // your code goes here unsigned short int t; cin>>t; while(t--){ unsigned short int n; unsigned long int p; cin>>n>>p; unsigned long int d[n]; for(unsigned short int i=0;i<n;i++) cin>>d[i]; bool flag=true; for(unsigned short int i=n-1;i>=0;i--) { if(p%d[i]!=0) {flag=false; int x=p/d[i]; d[i]=x; p-=d[i]*x; } else d[i]=0; } if(flag) cout<<"YES"; else cout<<"NO"; for(unsigned short int i=0;i<n;i++) cout<<" "<<d[i]; cout<<endl; } return 0; }

In your second for, you should be testing strictly for i>0, otherwise you're reaching -1, but as you are using unsigned, it becomes 65535; either way, signed or unsigned, you're out of bounds

In your second for, you should be testing strictly for i>0, otherwise you're reaching -1, but as you are using unsigned, it becomes 65535; either way, signed or unsigned, you're out of bounds

hi

hi guys this code: istream& operator >>(istream& in, ImpiantoSciistico& I) { in>>I.size; I.max = (I.size+1)*2; I.pista = new string[I.max]; I.difficulty = new Difficulty[I.max]; for (int i=0; i<I.size; i++) { in>>I.pista[i]>>I.difficulty[i]; } return in; } //Difficulty is enum the compiler throws this error error: no match for 'operator>>' (operand types are 'std::basic_istream' and 'Difficulty') in>>I.pista[i]>>I.difficulty[i];

Do you have >> operator overload for Difficulty?

Do I need to overload it for enums?

its a class

use IDA or something

Sorry, what is IDA?

IDA disassembler, shows you asm code and pseudo-C code

Sorry, what is IDA?

Hi, can I ask about decompile a dll file to have the source-code in cpp or it's off topic?

hey anybody here can help with a noob problem? i would like to get a float** from a vector<float>. say there are 6 items in the vector and i want to split them into 2 buckets with each has 3, ending up with a float**

Hi

You must manually create the float**, as vector<T> is basically a T*