Nope the exact opposite

I still don't get what you mean, sry

int MAKE_ID("i") = 0; ++i;

Thats no use imo

There are use cases for it you just didnt come across one

Can you please demonstrate cases when you need this feature?

Going to be a bit specific but recently i wrote a formant speech synthesizer in which i needed to parse phonemes and match them with the members of the voicebank struct's members, which are named accordingly with the phonemes

Going to be a bit specific but recently i wrote a formant speech synthesizer in which i needed to parse phonemes and match them with the members of the voicebank struct's members, which are named accordingly with the phonemes

is there a way to force passing my object by reference to a template function that accepts a deduced parameter by value? I have a variadic template function that accepts a pack of deduced values like template<typename... Args> void MyFunction(Args... args) {...} and I want to decide whether my arguments should be passed by reference or by value when I call this function

is there a way to force passing my object by reference to a template function that accepts a deduced parameter by value? I have a variadic template function that accepts a pack of deduced values like template<typename... Args> void MyFunction(Args... args) {...} and I want to decide whether my arguments should be passed by reference or by value when I call this function

It didn't actually make it more clearer how would you use is in code 🤷‍♂️. But Okay. I'm trying to avoid using macros as much as possible. They are "bad"

matching the parsed phonemes, which are strings, with the struct members.

std::ref

You can use cref, ref wrapper https://en.cppreference.com/w/cpp/utility/functional/ref

Sasriyakal

Sat shri akal *

#include<stdio.h> void main() { char STR[100],PAT[100],REP[100],ans[100]; int i,j,c,m,k,flag=0; printf("\nEnter the MAIN string: \n"); fgets(STR,sizeof(STR),stdin); printf("\nEnter a PATTERN string: \n"); fgets(PAT,sizeof(PAT),stdin); printf("\nEnter a REPLACE string: \n"); fgets(REP,sizeof(REP),stdin); i = m = c = j = 0; while ( STR[c] != '\0') { // Checking for Match if ( STR[m] == PAT[i] ) { i++; m++; flag=1; if ( PAT[i] == '\0') { //copy the REP string to ans string in the place of pattern matching. for(k=0; REP[k] != '\0';k++,j++) ans[j] = REP[k]; i=0; c=m; } } else //mismatch { ans[j] = STR[c]; j++; c++; m = c; i=0; } } if(flag==0) { printf("Pattern doesn't found!!!"); } else { ans[j] = '\0'; printf("\nThe RESULTANT string is:%s\n" ,ans); } }

Design, Develop and Implement a Program in C for the following operations on Strings a. Read a main String (STR), a Pattern String (PAT) and a Replace String (REP) b. Perform Pattern Matching Operation: Find and Replace all occurrences of PAT in STR with REP if PAT exists in STR. Report suitable messages in case PAT does not exist in STR.

/report @nimeteee pm'ing shit things ;-;

@nimeteee you have broken the rules several times, are you aware?

Design, Develop and Implement a Program in C for the following operations on Strings a. Read a main String (STR), a Pattern String (PAT) and a Replace String (REP) b. Perform Pattern Matching Operation: Find and Replace all occurrences of PAT in STR with REP if PAT exists in STR. Report suitable messages in case PAT does not exist in STR.

Eg.VOWEL----V*W*L V*W*L---VOWEL

How can i get back to a string after changing its vowel to *

you process the whole array in a loop and with a switch check if the current char is one of the 5 vowels (capital or not)

How would i come to know that they will be at the same position....consider INDIA as string

How can i get back to a string after changing its vowel to *

You can't, unless you save the vocals in order somewhere else

you don't need to, you are using a loop and a switch case block checking every single char of the string

I have tried this....but it fails at some test cases....where same vowels are present

If you save them, then it's just a question of looping through the saved vowel and assign then to their position

you are either doing the loop wrong or you are not checking for capitals

for (i = 0; i < sizeof(string); i++) { switch (string[i]) { case 'a': string[i] = ' '; break; case 'e': string[i] = ' '; break; case 'i': string[i] = ' '; break; case 'o': string[i] = ' '; break; case 'u': string[i] = ' '; break; } }

I don't see how this would work in any way

for (i = 0; i < sizeof(string); i++) { switch (string[i]) { case 'a': string[i] = ' '; break; case 'e': string[i] = ' '; break; case 'i': string[i] = ' '; break; case 'o': string[i] = ' '; break; case 'u': string[i] = ' '; break; } }

How would it work??

he just needs to replace every vowel with a space, right?

it checks every char of the string if it is a vowel

use a support array then