@programminginc - страница 2076

Marián

example of player::player

Marián

this happens without pragma -> says i redefine the class, the only thing i do is inheritance tho

Mat

why does this happen when i add #pragma once

That's not standard

Marián

That's not standard

my bad, i didn't put my header into #define #enddif

Marián

but i still have this issue

Anonymous

my bad, i didn't put my header into #define #enddif

That's called include guards

Marián

yup

Marián

but why do i get this bunch of errors

Marián

Anonymous

You've declared but not defined functions

Marián

hmm

Francisco

For the record, try to post a minimal example that reproduces your problem, so we can compile it and figure out what's going on

Mat

For the record, try to post a minimal example that reproduces your problem, so we can compile it and figure out what's going on

I agree. I see too much stuff on the screen to understand what's going on

Marián

ok wait

Marián

is pastebin enough or is it better for you if I send entire project

Marián

it's small like 4 source files

Mat

Try to reproduce your error with a minimal project

Marián

uh ok

Marián

btw do i have to implement virtuals in c++?

Marián

i was looking for something like abstract in C# but found only virtual modifier

Marián

do i have to implement it in base class?

Anonymous

To make a class abstract you need to declare at least one member function as pure virtual: virtual foo() = 0;

Anonymous

And you need to declare a destructor to be virtual virtual ~MyClass() = default;

Anonymous

And you need to declare a destructor to be virtual virtual ~MyClass() = default;

C#?

Anonymous

C#?

C++

Anonymous

And you need to declare a destructor to be virtual virtual ~MyClass() = default;

Is this necessary for making a class abstract?

Anonymous

Even though without this may lead to some random behaviour at times when you delete the derived object using Base's pointer.

Anonymous

Is this necessary for making a class abstract?

It's necessary for making class polymorphic and behave correctly

Anonymous

Even though without this may lead to some random behaviour at times when you delete the derived object using Base's pointer.

Yes

Anonymous

BTW, polymorphic classes are those which have a virtual function or inherit one. Right?

Anonymous

so both base and derived come are polymorphic?

Francisco

is pastebin enough or is it better for you if I send entire project

Never send an entire project. Just a code snippet that reproduces your problem. Also, by doing that every time you a face a bug, you normally end up finding it before asking for help

Marián

thanks, already fixed it, i just forgot to link lib to qmake...

Francisco

In fact, I've found a couple compiler bugs by doing that

Anonymous

Hello

Anonymous

I need c software for mac

Anonymous

Please help where I download it?

Mat

I need c software for mac

What?

Mat

An editor? An ide? A compiler?

Anonymous

What?

I need c programming software for mac

Mat

I need c programming software for mac

Answer me!

Anonymous

hello i want to start learning C++ can anyone please help

Anonymous

Answer me!

For practice where I practice

Mat

For practice where I practice

Mat

hello i want to start learning C++ can anyone please help

Well, start!

Anonymous

BTW, polymorphic classes are those which have a virtual function or inherit one. Right?

Yeah

Artöm

VSCode is not good for C++ development (but still some people use it) especially for Qt

Im ok with it after learned how to debyg and stuff

Anonymous

how to look inside the classes of the c++ standard'

Anonymous

how to look inside the classes of the c++ standard'

You don't need that

Anonymous

You don't need that

I wanted to check what all member functions are present in the ostream class

Anonymous

Why...

Anonymous

Why...

I read that The out is of type std::ostream. This can not be copied (the copy constructor is disabled). So you need to pass by reference.

Artöm

how to look inside the classes of the c++ standard'

cppreference.com

Anonymous

I read that The out is of type std::ostream. This can not be copied (the copy constructor is disabled). So you need to pass by reference.

So?

Anonymous

So, wanted to see how the copy constructor looks inside the ostream class

Anonymous

what does disabled mean?

Anonymous

So, wanted to see how the copy constructor looks inside the ostream class

There's no copy constructor

Anonymous

There's no copy constructor

so the default one runs right?

Artöm

It is deleted or privated

Artöm

so the default one runs right?

No, it is explicitly deleted

Anonymous

For example: ostream(const ostream&) = delete;

Anonymous

For example: ostream(const ostream&) = delete;

aah !! i didn't know that.

Anonymous

For example: ostream(const ostream&) = delete;

It's C++11 feature In early C++ it looks like: private: ostream(const ostream&);

Anonymous

It's C++11 feature In early C++ it looks like: private: ostream(const ostream&);

So, that's why ostream& operator<<(ostream& out, Objects const& obj) ostream is returned by reference and called by reference so that the privated copy constructor doesn't get called?