https://pastebin.com/fFQ1mSaq

look good

but it does not work

the program not works

the program not works

Where?

cmd

I see only Valore2 = valore1/2 Printf(valore1)

https://pastebin.com/yWXfw2qP

24

But you print valore1. Not valore2

But you print valore1. Not valore2

but it not work

but it not work

but it not work

valore 2

Multi-dimensional arrays cannot be handled like this AFAIR.

Hi you were correct, new expression decays arrays to pointer, fuck! I'm disappointed. BUT this is not related to the code snippet, actually, because there was no arrays originally and both pointers and references would starve from array to pointer decay similarly.

The issue I have with the original snippet is that even tho it is syntactically correct it is not semantically correct, it doesn't mean to a human what you would expect it to mean, as, alone, I means that the allocated value is not owned by the function (it is a reference)

And worse than that, nobody actually have any semantic form stating it owns it

For owning, we must use smart pointers

And here who owns the value?

I will tell you who owns that pointer removed reference, it is the Illuminati and the freemasons that have shared ownership of it

This is unknown. As it would be with pointer instead of reference

群里有中国人吗

Guys how to allocate a stack in c ?

what do you mean by stack? the data structure or machine memory area used to call functions?

Yes

Guys how to allocate a stack in c ?

As u like

Your english is so good :D

Thanks for the compliment

Will you please answer my question?

Will you please answer my question?

what do you mean by stack? the data structure or machine memory area used to call functions?

Which one ?

I mean the data structure

ok, I see, There is NO standard data structures like Vector List, etc , including stack, in the standard library of C, so you cannot create stack. There are 3 options you can find some (non-standard) library for C, implementing stack you can write your own implementation or You can use C++ and std::stack

It is on the same level of cleverness as volatile int f() { return 4; }

The code here should read: int f() volatile { ... } For c++ functions it can for the most compilers only appear on member functions and not standalone functions. Volatile on a member function is meant to tell the compiler no optimizations on the function and the object it is declared/defined in because the code can be called from outside the app execution context at runtime... If you wanted const just use it, do not try to be smart, it will only make life difficult for yourself.

The code here should read: int f() volatile { ... } For c++ functions it can for the most compilers only appear on member functions and not standalone functions. Volatile on a member function is meant to tell the compiler no optimizations on the function and the object it is declared/defined in because the code can be called from outside the app execution context at runtime... If you wanted const just use it, do not try to be smart, it will only make life difficult for yourself.

The code here should read: int f() volatile { ... } For c++ functions it can for the most compilers only appear on member functions and not standalone functions. Volatile on a member function is meant to tell the compiler no optimizations on the function and the object it is declared/defined in because the code can be called from outside the app execution context at runtime... If you wanted const just use it, do not try to be smart, it will only make life difficult for yourself.

That is not what volatile mean, volatile only operates on memory writes and read and specify said write or read my have side effects, it does not affect optimization

Read your compiler docs... volatile disables all ootimizations

Also if you want to be smart, you should read what people say, it would help, instead of blowing like an idiot and pretending you did any reading of the standard

I've worked 26 years on c/c++ - no need for the std