klimi
You even said how to program it, so I dont... Nvm
Anonymous
Who can send me a pdf
Duncan
😂😂🙌
Dima
do as you like
Anonymous
Ok
Emir
can someone help me about algorithm?
I_Interface
can someone help me about algorithm?
U need it, not us.
Write it on a list of paper. Step by step.
Ask if u will have a problem with code.
Emir
Anonymous
Anonymous
You start with a number (non-zero natural number). And, if you have an even number divide it by 2, if it's an odd number multiply it by 3 and add 1. Keep repeating this process. The fun fact is that you will always end up to 1.
So, let's try this game with say a number like 17. 17 --> 52 --> 26 --> 13--> 40-->20--> 10--> 5--> 16--> 8--> 4-->2 -->1.
Let's try a different number say 2019. 2019--> 6058-->3029-->9088-->4544-->2272-->1136-->568-->284-->142-->71-->214-->107-->322-->161-->484-->242-->121-->264-->132-->66-->33-->100--> 50-->25-->76-->38-->19-->58-->29-->88-->44-->22-->11-->34-->17
It's a long standing conjecture that any number would eventually end up to 1 in this game.
I was working on this program but i cant figure out what is wrong with my odd numbers it's looping the odd numbers only
Anonymous
https://pastebin.com/YztLdcVa
Anonymous
Here is the program
Anonymous
Hi All
Anonymous
Hmm
Anonymous
Can You Suggest me Any others groups like this?
Anonymous
Iam New to Programming
Anonymous
Ask there
Anonymous
#ot
Ilya
Anonymous
i install new version of gcc on my computer but for some reason when i do gcc -v it say old version , but when i try to reinstall it says it has the latest version already
Javi
i install new version of gcc on my computer but for some reason when i do gcc -v it say old version , but when i try to reinstall it says it has the latest version already
The new version isn't in your path, check what is in your path variable
Anonymous
Javi
That depends on you SO
Anonymous
Humbles-MacBook-Pro:~ humblerise$ brew upgrade gcc
Error: gcc 9.2.0_1 already installed
Humbles-MacBook-Pro:~ humblerise$ gcc -v
Using built-in specs.
COLLECT_GCC=gcc
COLLECT_LTO_WRAPPER=/usr/local/libexec/gcc/x86_64-apple-darwin15.6.0/7.1.0/lto-wrapper
Target: x86_64-apple-darwin15.6.0
Configured with: ../gcc-7.1.0/configure --enable-languages=c++,fortran
Thread model: posix
gcc version 7.1.0 (GCC)
Javi
I'm not very familiar with mac. But google how does it set the path and how does it handle different versions. In linux it uses the alternative links, but I don't know how it works with apple
Anonymous
Javi
The system variable $PATH tells the so where to look for executables when you type a command without the path. When you write, for example, ls, you are actually executing /usr/bin/ls (in linux). This can only happen if the directory /usr/bin is included in the path
Anonymous
Anonymous
so my path is set wrong , or installed the new version in the wrong path?
Javi
It may be that, or you have to reset a link. In linux, when you install two versions of a program (for example gcc), gcc is actually a link to one version, that acts as a default. That way when you type gcc, you are actually executing gcc-v6, and if you want to execute other version, you have to type explicitly gcc-v7
Javi
As I said, this is linux, I don't know in mac
Anonymous
should be similar if not the same , uses same commands
Javi
Maybe
Javi
Try "whereis gcc"
Javi
There, check if gcc is a link
Javi
ls -la /usr/bin/gcc
Javi
ls -la /usr/bin/gcc*
Anonymous
thats what its saying
Anonymous
/usr/bin/gcc and /usr/local/bin/gcc
Anonymous
i see two gcc ,
Francisco
That's the best way to link executables
Javi
It doesn't look like links
Javi
Better check in google how does mac handle with versions
Javi
you can also execute /usr/bin/gcc -v and /usr/local/bin/gcc -v
Javi
To see which versions are they
Ибраги́м
https://www.reddit.com/r/cpp/comments/dn8qrq/unproductive_challenge_longest_variable/?utm_source=share&utm_medium=web2x
MᏫᎻᎯᎷᎷᎬᎠ
https://www.reddit.com/r/cpp/comments/dn8qrq/unproductive_challenge_longest_variable/?utm_source=share&utm_medium=web2x
Why should someone read this?!
Anonymous
why are all the currency have the same output?
https://pastebin.com/FPyUdQZe
Talula
why are all the currency have the same output?
https://pastebin.com/FPyUdQZe
What in the world is 1 float convert(float fPeso, float fRate)
2 {
3     float USD, Euro, Japan, GBP, CHF;
4    
5     USD = fPeso / 51.1811;
6         return USD;
7     Euro = fPeso / 56.9610;
8         return Euro;
9     Japan = fPeso / 0.47181;
10         return Japan;
11     GBP = fPeso / 65.9760;
12         return GBP;
13     CHF = fPeso / 51.7338;
14         return CHF;
15 }
Talula
It will always return USD...
Anonymous
how would I make it return its own currency using one function?
Anonymous
Talula
float convert(float fPeso, float fRate)
{
return fPeso / fRate;
}
Anonymous
nice
Anonymous
thanks it finally works
Pavel
Do we have some mechanism to have different class typedefs that are not convertible between each other?
E.g. I want to have std::string analogs for ID, path and localizable string. And I want to ensure that I can't pass a path as ID or plain std::string as a localizable string to some function. Also, I want to ensure that they can't be compared via == or !=. E.g. (path == id) should give a compilation error. Also I want to be able to write template specialization for each type (so I can generate path picker field for path in my editor instead of text field) Other than that the classes should act as std::string.
Basically I want to achieve something similar with what golang type aliases do.
How can I achieve that except for writing my own string from scratch or making a wrapper around std::string and wrap every std::string function in it?
I'm using C++17
many
How to implement a tree with different types of nodes and the parent node does not know the types of child nodes when initialized/compile time
Eg.
template<...>
class Node<...>{
T foo;
Node<...>* next
...
};
Pavel
Do we have some mechanism to have different class typedefs that are not convertible between each other?
E.g. I want to have std::string analogs for ID, path and localizable string. And I want to ensure that I can't pass a path as ID or plain std::string as a localizable string to some function. Also, I want to ensure that they can't be compared via == or !=. E.g. (path == id) should give a compilation error. Also I want to be able to write template specialization for each type (so I can generate path picker field for path in my editor instead of text field) Other than that the classes should act as std::string.
Basically I want to achieve something similar with what golang type aliases do.
How can I achieve that except for writing my own string from scratch or making a wrapper around std::string and wrap every std::string function in it?
I'm using C++17
Found a way how to (mostly) achieve that
https://pastebin.com/Vrt5nBtD
It seems to be working well.
Conversations between types will be costly (a string copy) but in my case this is OK,
Anonymous
template <typename T>
using int_map = std::map<int, T>;
Anonymous
template <typename T>
using int_map = std::map<int, T>;
@gameraccoon typedefs cannot