@programminginc - страница 1891

Jaimy de Vries

I am trying to compile quite a list of things into 1 runnable solution for the web but so far im failing it pretty big time

Jaimy de Vries

#Wanttopay for solution

Anonymous

good night friends

Anonymous

anybody want some pepsi

professor

hey guys

Jaimy de Vries

anybody want some pepsi

No I want a good compile solution for my c++ to web task

Sandeep

Hello

Rushikesh

/java

Rushikesh

How do java program questions like area of the circle and find in without perimeter how to do???

Rushikesh

Sorry for English

Talula

How do java program questions like area of the circle and find in without perimeter how to do???

This is not Java Room... wrong number...

Jaimy de Vries

well if u looking to convert c or c++ to java it would be xD

Talula

well if u looking to convert c or c++ to java it would be xD

Then it'll never be...

Talula

If you're converting from Java to C++ then it might be.

Jaimy de Vries

Im looking for a way to convert c++ to javascript actually or anything to make our game client for multiplayers able to load in web browsers or mobile devices

Jaimy de Vries

without going through to much recoding if possible

Anonymous

Im looking for a way to convert c++ to javascript actually or anything to make our game client for multiplayers able to load in web browsers or mobile devices

You can try to use C++ in the client side with WebAssembly

Talula

Im looking for a way to convert c++ to javascript actually or anything to make our game client for multiplayers able to load in web browsers or mobile devices

All you'll have to change is your front end of the game, most of your graphics file will remain and most of your logic will remain same.

Jaimy de Vries

@danya thats what im trying to find out my client exists out of folders, images, exe, json and some other files I just wonder how to side it with Web Assembly I cant find a live example of do this and this is my problem at the moment

Jaimy de Vries

so its a bit as being stuck in the hay looking for a nail

Anonymous

@danya thats what im trying to find out my client exists out of folders, images, exe, json and some other files I just wonder how to side it with Web Assembly I cant find a live example of do this and this is my problem at the moment

I don't understand you

Talula

@danya thats what im trying to find out my client exists out of folders, images, exe, json and some other files I just wonder how to side it with Web Assembly I cant find a live example of do this and this is my problem at the moment

There is no direct conversion from C++ to JavaScript, but your logic files will be almost converted 1 to 1... but your front end will be different.

Jaimy de Vries

There is no direct conversion from C++ to JavaScript, but your logic files will be almost converted 1 to 1... but your front end will be different.

So frontend would need to be rebuild entirely you mean?

Talula

So frontend would need to be rebuild entirely you mean?

Yes you have to because graphics are handled totally differently in JavaScript compared to C++, though it's simpler in JavaScript.

Ilya

Generate all combination of two point s multimap( distance => pair of points), rbegin()

Ilya

What time complexity can we hope for, optimally?

N*N

Ilya

Not an efficient approach, brute force O(n^2)

There is no shorter solution

Anonymous

N*N

No, later I decided it can be done in less than that, NlogN

Anonymous

There is no shorter solution

Convex hull

klimi

Yo yoo

Anonymous

Hi

Ибраги́м

https://www.reddit.com/r/cpp/comments/dc73r1/even_the_ai_knows/?utm_medium=android_app&utm_source=share

Javi

There is no shorter solution

I think there is. You can find the average position of the points, convert the coordinates to spherical, and just pick the point with the maximum radius. It should be O(n)

A

Heyy! Whats the difference between C and C++ Whatt should i learn? I am beginner!

A

Can someone give me a full playlist of tutorial on C++

Talula

I think there is. You can find the average position of the points, convert the coordinates to spherical, and just pick the point with the maximum radius. It should be O(n)

That'll not give you distance between 2 points, it'll give you the maximum distance of a single point.

Talula

If you take first and second distances or "radius" it'll only give you distance between these two points to the center of average circle...

Talula

It will not give you the distance between two points...

Javi

Right, it will be an upper limit

Javi

But you can repeat the process setting the origin of the coordinates to the point that you found in the previous step. Now the new maximum radius will be the maximum distance between two points (I think)

A

Heyy! Whats the difference between C and C++ Whatt should i learn? I am beginner!

..

Anonymous

Heyy! Whats the difference between C and C++ Whatt should i learn? I am beginner!

The difference is that C is the mother of C++

Talula

But you can repeat the process setting the origin of the coordinates to the point that you found in the previous step. Now the new maximum radius will be the maximum distance between two points (I think)

It'll never be maximum distance between 2 points, it'll be maximum distance between a point and center of average circle.

Anonymous

But you can repeat the process setting the origin of the coordinates to the point that you found in the previous step. Now the new maximum radius will be the maximum distance between two points (I think)

You mean the minimum radius that encloses all the points? That would be correct in that case, because the two points with the largest distance would become the end points of diameter of the sphere. Not O(n) though

Anonymous

Can someone give me a full playlist of tutorial on C++

Read the books

Anonymous

Can someone give me a full playlist of tutorial on C++

#cppbookguide

Talula

You mean the minimum radius that encloses all the points? That would be correct in that case, because the two points with the largest distance would become the end points of diameter of the sphere. Not O(n) though

Largest distance to what?

Talula

If you're talking about largest distance to center of the average circle it wouldn't work.

Anonymous

Largest distance to what?

Points with the largest distance between each other

Talula

Points with the largest distance between each other

How would you find the largest distance using a circle?

Javi

It'll never be maximum distance between 2 points, it'll be maximum distance between a point and center of average circle.

That's the first step. In the second step, radius 0 is at the point that you found before, so the new maximum radius will be the maximum distance between two points in the set

Anonymous

How would you find the largest distance using a circle?

Basically expand the circle then check if all the points are in the circle yet, then repeat till no point is outside the circle

Talula

Basically expand the circle then check if all the points are in the circle yet, then repeat till no point is outside the circle

That will give you distance between the point x,y and center of the circle... 0,0...

Javi

You mean the minimum radius that encloses all the points? That would be correct in that case, because the two points with the largest distance would become the end points of diameter of the sphere. Not O(n) though

The minumum radius that encloses all the points, being centered at the point that is fartherst from the mean position. It's O(n), but with a lot of overhead, so it is only worth if the number of points is really big

Talula

Not x1,y1 and x2,y2

Anonymous

Not x1,y1 and x2,y2

0,0 would be the midpoint of these two, if these two would be the points that have the largest distance between them

Anonymous

The minumum radius that encloses all the points, being centered at the point that is fartherst from the mean position. It's O(n), but with a lot of overhead, so it is only worth if the number of points is really big

I can think of an approach similar to binary search, but that won't be linear. How are you getting O(N)?

Javi

Convert to spherical units: O(n)

Talula

0,0 would be the midpoint of these two, if these two would be the points that have the largest distance between them