Google for IWallparer interface As far as I know it can give rects of all possible monitors

Google for IWallparer interface As far as I know it can give rects of all possible monitors

I will try . Thanks for all who tried help me

Google for IWallparer interface As far as I know it can give rects of all possible monitors

nothing like this exists lol

iwallparer?

Probably I confused the name

IDesktopWallpaper is the right one

https://docs.microsoft.com/en-us/windows/win32/api/shobjidl_core/nn-shobjidl_core-idesktopwallpaper

Can anyone help me in zombies of codechef

Can anyone help me in zombies of codechef

lol We don't help with things like that Only with code problems / questions about C/C++

Can anyone help me in zombies of codechef

No.

So hard to read the rules :D

Gi

So hard to read the rules :D

Sometimes even I like to break some rules. But imagine getting into a friendly community and ruining it lol!

Why signed overflow? Does that mean if x is INT_MAX then x+1 will overflow?

Why signed overflow? Does that mean if x is INT_MAX then x+1 will overflow?

Yep

Yep

Doesn't the language define that x+1 will become INT_MIN? Hence, UB?

Doesn't the language define that x+1 will become INT_MIN? Hence, UB?

The language doesn't define anything. That's why it's UB

okk. So, if the language doesn't define anything then on whom does the output of program depend upon?

okk. So, if the language doesn't define anything then on whom does the output of program depend upon?

Sometimes the compiler, sometimes the hardware. Sometimes it's totally casual

Surely it's not something you can know while writing your code

Surely it's not something you can know while writing your code

So, printf("%d %d", ++x, x++); is one of them?

UB?

lol We don't help with things like that Only with code problems / questions about C/C++

Lol this is a problem name😑😑

Lol this is a problem name😑😑

Don't ask, just show ur problem with code

#noendl

This is a bit biased towards people using endl without understanding it. I would actually advise using it for output on std::cerr

This is a bit biased towards people using endl without understanding it. I would actually advise using it for output on std::cerr

I always laugh when he says “Bullshit!” and “..here’s picture of a cat”

All those who learn c++ become as wicked as the compiler

All those who learn c++ become as wicked as the compiler

lol

All those who learn c++ become as wicked as the compiler

But miserably fail

is it possible to run c++ codes in memory or just program some functions of the code running in memory?

Can i anyone send me one good project on c++

???

I need it urgently sir ...

/saved

/get goodcodingmentality

#goodcodingmentality

#learn

#callingfunction

#bingo

#awesomeness

I understand that endl is "\n" + flush and it is 6 times slower than "\n" But, why would anyone use "\n" if it is not getting flushed to the output when the programmer wants it to and getting flushed after sometime which would look like a bad formatting of the output.

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I understand that endl is "\n" + flush and it is 6 times slower than "\n" But, why would anyone use "\n" if it is not getting flushed to the output when the programmer wants it to and getting flushed after sometime which would look like a bad formatting of the output.

It won't, unless you print from multiple threads. If you just do something cout << "test1\n"; cout << "test2\n"; It will print what you expect all of the time. It what do you mean by bad formatting.

I mean cout << "test1\n"; cout << "test2\n"; cout << "test3\n"; will sometimes give: test1test2 test3 2 newline after test2

I mean these new lines will be printed sometime later and not just where we want them to be printed

How to use printf_() in gcc? It’s showing error.

*printf_s()

is it possible to run c++ codes in memory or just program some functions of the code running in memory?

What do you even mean?

How to use printf_() in gcc? It’s showing error.

The same way as printf

The same way as printf

Well it gives error.

In Linux environment

Well it gives error.

Cool

I mean cout << "test1\n"; cout << "test2\n"; cout << "test3\n"; will sometimes give: test1test2 test3 2 newline after test2

No it won't, why it should? You can think of \n as a symbol (as it in text files).

In other words "flush" means in this case something like "send buffer to print and clear it". You can send a buffer with \n in it as well as without any. Flush is unrelated to newline.

#learn

In other words "flush" means in this case something like "send buffer to print and clear it". You can send a buffer with \n in it as well as without any. Flush is unrelated to newline.

stop using endl. Watch this video https://www.youtube.com/watch?v=GMqQOEZYVJQ from one of the expert in c++

stop using endl. Watch this video https://www.youtube.com/watch?v=GMqQOEZYVJQ from one of the expert in c++

Why do you send it to me

It doesn't seem as a great course

In other words "flush" means in this case something like "send buffer to print and clear it". You can send a buffer with \n in it as well as without any. Flush is unrelated to newline.

Can you tell how does buffer works while printing anything?

Hi

We need a c++ freelancer for long time development with minimum 5years experience...

We need a c++ freelancer for long time development with minimum 5years experience...

experience with what, in particular ?

I mean cout << "test1\n"; cout << "test2\n"; cout << "test3\n"; will sometimes give: test1test2 test3 2 newline after test2

Never. The output string will always be "test1\ntest2\ntest3\n"

I need it urgently sir ...

Why? GitHub is full of CPP projects that you can contribute to

We need a c++ freelancer for long time development with minimum 5years experience...

Read the rules

Can anyone help me

I got to solve two question for tomw test

Can anyone help me

Don't ask about help Show ur problem first

I hv to write a program calculate sum of salalry of one employee for 12 months n decduction using do while loop

the do while will only execute once, since i will be 2 at that time.

and 2 >= 12 is false.

while(i <= 12);

Also, your function is defined to have a void return type

but you are returning an int.

Ya

Got it

Thx bro