@programminginc - страница 1743

#include <iostream> #include <typeinfo> int main() { // Type alias using T = char; // Array size constexpr size_t array_size = 10; // Declaring an array T array[array_size]; // Declaring a pointer T* pointer; std::cout << "Array size: " << sizeof(array) << "\n"; // 10 = array_size * sizeof(T) std::cout << "Pointer size: " << sizeof(pointer) << "\n\n"; // sizeof(void*) std::cout << "typeof(array): " << typeid(array).name() << "\n"; // char[10] = T[array_size] std::cout << "typeof(pointer): " << typeid(pointer).name() << "\n\n"; return 0; }

Anonymous

Console output: Array size: 10 Pointer size: 4 typeof(array): char [10] typeof(pointer): char *

Anonymous

Is it convincing enough?

Anonymous

#include <iostream> #include <typeinfo> int main() { // Type alias using T = char; // Array size constexpr size_t array_size = 10; // Declaring an array T array[array_size]; // Declaring a pointer T* pointer; std::cout << "Array size: " << sizeof(array) << "\n"; // 10 = array_size * sizeof(T) std::cout << "Pointer size: " << sizeof(pointer) << "\n\n"; // sizeof(void*) std::cout << "typeof(array): " << typeid(array).name() << "\n"; // char[10] = T[array_size] std::cout << "typeof(pointer): " << typeid(pointer).name() << "\n\n"; return 0; }

The console output will be different if you are going to compile it using gcc/clang

Anonymous

But the point will be the same, only the representation differs

Anonymous

@k_vark, @bi_kash, what do you think?

Anonymous

http://thats-a.link/77BLnXt.png

Anonymous

Somehow breakpoints ain't working

I_Interface

Somehow breakpoints ain't working

linux?

Anonymous

Windows

Anonymous

I'm using CMAKE

I_Interface

Windows

use visual studio

Anonymous

And http://thats-a.link/8LnjyYV.png

kvark

@k_vark, @bi_kash, what do you think?

yes, its true

Anonymous

Do you need visual studio to debug?

Anonymous

Wut

I_Interface

Do you need visual studio to debug?

nope, but it has more options for that

Anonymous

i'm wondering why its not working

Anonymous

Visual Studio Code isn't an IDE

Anonymous

You need IDE to debug

I_Interface

Visual Studio Code isn't an IDE

and yes

I_Interface

Danya is right

Anonymous

#include <iostream> #include <typeinfo> int main() { // Type alias using T = char; // Array size constexpr size_t array_size = 10; // Declaring an array T array[array_size]; // Declaring a pointer T* pointer; std::cout << "Array size: " << sizeof(array) << "\n"; // 10 = array_size * sizeof(T) std::cout << "Pointer size: " << sizeof(pointer) << "\n\n"; // sizeof(void*) std::cout << "typeof(array): " << typeid(array).name() << "\n"; // char[10] = T[array_size] std::cout << "typeof(pointer): " << typeid(pointer).name() << "\n\n"; return 0; }

yes. thanks.

Anonymous

Why dous debug work fine for like java lol

Anonymous

And a few other langs

Anonymous

Console output: Array size: 10 Pointer size: 4 typeof(array): char [10] typeof(pointer): char *

then why does char * const ptr = array ; doesn't complain?

Anonymous

Whoops fixed that

Anonymous

I somehow had it set to release mode...

Anonymous

http://thats-a.link/4bPUDJt.png

Anonymous

It compiles fine but vscode is bitching about that header

Anonymous

then why does char * const ptr = array ; doesn't complain?

Because arrays can be implicitly casted to pointers to a first element

Anonymous

visual studio dous not complain about it at all

Anonymous

Visual Studio Code isn't an IDE

Anonymous

It is a text editor

Anonymous

It doesn't have neither compiler nor debugger

olli

http://thats-a.link/77BLnXt.png

try switching to "CMake: Debug" instead of Release

Ludovic 'Archivist'

While using inline function can someone please tell me that whether the entire code in the function is substituted in place of the function call or whether a part of it is substituted

Since inline is unrelated to that, maybe maybe not. Inline is an advise for the linker meaning the function may be defined in multiple translation units.

ozxx

/opencv

Tom

#include<stdio.h> #include <stdlib.h> int main() { unsigned long int n,a; int i=1,f=-1,s=1,t=0,noe=0,nod=0,d,sum=0; scanf("%uld",&n); a=n; while(a>0) { d=a%10; if(d%2==0) { noe++; } else { sum=sum+d; nod++; } a=a/10; } if(noe>=nod) { while(t!=n) { t=f+s; printf("%d ",t); f=s; s=t; } } else { while(i<n) { printf("%d ",i); i=i+sum; } } return 0; }

Tom

This is the question

Tom

The given examples are working perfect.. Bt there are 8 hidden test cases

Death

He hasn't mentioned that count(even no.s) >= count(odd no.s)

Death

Check for digits in given number N

Death

If the count(even digits)>=count(odd digits)