Hey ! Danya Why is "abc" considered const char * and not const char[n+1] ?

what are the additional functionalities that you are talking about? Can you elaborate on those algorithms?

I mean if you want to make a function that does something with a string (regardless its size) you need to pass a pointer to const char anyway.

OK, that is convincing to understand. But, I am not able to make choice over what are string literals? Are they const char* or const char[]?

OK, that is convincing to understand. But, I am not able to make choice over what are string literals? Are they const char* or const char[]?

a string literal is of type const char[N]

any reference would help.

Regarding the documentation I've sent, it's const char[N] where N is size of the string + 1. https://en.cppreference.com/w/cpp/language/string_literal But it's C++, I don't have info about C, but guess that you can Google the specification for C.

any reference would help.

In the reference you provided right under the "const_cast" example, it is written that : In C, string literals are of type char[], and can be assigned directly to a (non-const) char*

Yes, but that's the general case of arrays. Two specific things here: first that the array is static so you don't need to care about its life time, the second is that you have a terminating character, so you don't care about storing the size. If you have (or allocate) an usual array and get a pointer to it, you need to store the size somewhere in order to work with the array through the pointer.

In the same para, It is also written that : but deprecated it, as literals are const in C++

and so const before char[] or char * should be used to prevent un-defined behaviour.

So, finally the conclusion is that : Originally, string literals are const char arrays. Right?

3rd point in the photo.

So, finally the conclusion is that : Originally, string literals are const char arrays. Right?

String literals are and have always been of type const char[N]

I hope you know correct but have a look at this: https://www.cs.uic.edu/~jbell/CourseNotes/C_Programming/CharacterStrings.html Check the 3rd point. Won't it give un-defined behaviour?

I hope you know correct but have a look at this: https://www.cs.uic.edu/~jbell/CourseNotes/C_Programming/CharacterStrings.html Check the 3rd point. Won't it give un-defined behaviour?

I didn't get why the contents of s7 should not be changed, why not?

Ok, seems like assigning to char[] creates a stack allocated array, that explains everything. https://www.geeksforgeeks.org/whats-difference-between-char-s-and-char-s-in-c/

Because it's UB https://wiki.sei.cmu.edu/confluence/plugins/servlet/mobile?contentId=87152214#content/view/87152214 Not sure how it works with char[]

Thanks. It works fine with char [] char str[] = "string literal"; str[0] = 'S';

It is an UB because it stores wtih an executable and has static storage duration. It is an UB when you are trying to change memory where the code is written

You should understand that when you start running your executable, all the machine code it contains goes to the RAM. And string literals are stored aside with machine code in some protected memory segment, I guess. So, changing a content of that protected memory is UB

Great, now string literals are stored in ROM, makes sense for causing UB. Does it only happens when use of pointer to string literal?

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Yes, because it points to an actual string literal When you initilize an array with string literal, it coipies the literal to stack memory

I am using dev c++

Dev C++ is not a compiler

Someone help to remove error

Whats the problem?

#include <stdio.h> void add(int a[10][10], int b[10][10], int m, int n) { int sum[m][n]; for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { sum[i][j] = a[i][j] + b[i][j]; printf("%d\t", sum[i][j]); } printf("\n"); } } void main() { int i,j,m,n,o,p; printf("Enter the no. of row and column of 1st matrix"); scanf("%d%d",&m,&n); printf("Enter the no. of row and column of 2nd matrix"); scanf("%d%d'",&o,&p); if(m==o && n==p) { int a[m][n]; printf("Enter the first matrix"); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); } } int b[m][n]; printf("Enter the second matrix"); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&b[i][j]); } } add(a, b, m, n); } }

First of all change return type to int. And just use the pointer to get the base address of the matrix.

Return type of main to int

Made int Now called function error

Guys does anyone have a starter book

So, finally the conclusion is that : Originally, string literals are const char arrays. Right?

Hi buddies, So I'm an newbie to programming and I have encountered a case for which I suppose qualifies as an authentic question in this awesome group. I am practising building programs which are easy to maintain br localizing the effects to a class's data members by accessing and manipulating the data members through their get and set functions. In this regard I have two data members for which I wish to change. After compiling, the set functions works well by changing the values but the get functions can only return one of the data member values ata time Now is there a way to write statements inside my get functions so that I can obtain all the changed data member values without having to create multiple get functions for each data member? Regards