I have to verify, but it is not accepted by the exercise..

Okay brother

/warn

Looooool

Okay brother

Thx bro

^•^

I have to verify, but it is not accepted by the exercise..

Can we do like.. We have 2 pointers.. prev:- pointing to previous node next:- pointing to present node that is inputted through keyword and we can compare like If(next->data == prev->data +1)

It could be a right solution, I went into hypnosis 🙂 I'll check!

I'll let you know soon..

I'll let you know soon..

Yes please

It could be a right solution, I went into hypnosis 🙂 I'll check!

that is right solution))

why is the j value 2 here? shouldn't it be 1? coz a[1] is 1 there and given statement is the post increment..so shouldn't the j value stay as 1?

why is the j value 2 here? shouldn't it be 1? coz a[1] is 1 there and given statement is the post increment..so shouldn't the j value stay as 1?

it is incremented when you do i=++a[1];

why is the j value 2 here? shouldn't it be 1? coz a[1] is 1 there and given statement is the post increment..so shouldn't the j value stay as 1?

i = ++a[1]; // i = 2, a[1] = 2 now

i = ++a[1]; // i = 2, a[1] = 2 now

yeah i=2,but why does it effect a[1]? i is just a variable right? why would assigning a variable effect array element?

yeah i=2,but why does it effect a[1]? i is just a variable right? why would assigning a variable effect array element?

array is just a pointer, so when u increment arr[index] u increment array element, not it's copy

try to declare const int arr[5] ... instead of int arr[5] ... for better understanding

okay... one more try int arr[2] = {1, 2}; // u create actually a pointer (int *) named arr, it //points to a //memory-area with size sizeof(int) * 2; int i = ++arr[0]; // here u just write this actually: int i = ++*(arr + 0); // so u increment variable, that locate at 'arr + 0' address

well thanks! that explains 😁

Hi, i'm newbie

Hi, i'm newbie

nohello.com

Hi, i'm newbie

Welcome

I ALWAYS get segmentation fault when i try to use 2D arrays or an array of strings. Any idea why?

I ALWAYS get segmentation fault when i try to use 2D arrays or an array of strings. Any idea why?

Show code

int main() { int ele,i,n,q; int row,column; cin>>n>>q; int array[100][100]; for(i=0;i<n;i++) { cin>>ele; for(int j=0;j<ele;j++) { cin>>array[i][j]; } } for(int k=0;k<q;k++) { cin>>row>>column; cout<<array[row][column]; cout<<"\n"; } return 0; }

its sort of a 2D array but number of elements in each row is not the same.. the number of elements is the first input in each line which i've taken as ele

im supposed to do dynamic memory allocation but i dont know how to do that in 2D

Can anyone write the code to this program ina ny language

no photo

My eeeyeeeees

/report read the rules

Well it is in the rules....

Ha ya

Can anyone write

Can anyone write the code to this program ina ny language

I can why?

Now we need it

im supposed to do dynamic memory allocation but i dont know how to do that in 2D

:/

Urgently

I can why?

Can u pls write

im supposed to do dynamic memory allocation but i dont know how to do that in 2D

u first need to allocate array of type** than allocate N arrays of type*

is vector of vectors a good idea? if yes how do you implement it?

Code and send

Now we need it

Like in that java group someone is taking exams so they need solutions

I don't want to be coworkers with them

What a bs

Can u pls write

I already said I can

Urgently

so you want us to do your homework, right now and for free? go away 😂

so you want us to do your homework, right now and for free? go away 😂

Its their assignment

u first need to allocate array of type** than allocate N arrays of type*

allocate each array using a for loop? :/

Its their assignment

Ha ya

im supposed to do dynamic memory allocation but i dont know how to do that in 2D

for example: //int arr[n][m]; int **arr = new int*[n]; for (int i = 0; i < m; ++i) arr[i] = new int[m];

for example: //int arr[n][m]; int **arr = new int*[n]; for (int i = 0; i < m; ++i) arr[i] = new int[m];

Wrong

for example: //int arr[n][m]; int **arr = new int*[n]; for (int i = 0; i < m; ++i) arr[i] = new int[m];

int arr = new int[n]; or int **arr = new int*[n]; ?

int arr = new int[n]; or int **arr = new int*[n]; ?

Second

Its their assignment

so?

whoops it took the asterisks as text formatting haha

int*[n] means pointer to an array?

int*[n] means pointer to an array?

It means array of pointers

yeah, that was error; already fixed

so?

Its not homework

Its different

i thought "arr" was the pointer array..?

Its not homework

of course its different but it is even worse then

so?

If I get paid, I can do someone's homework no problem

sounds like a nice business

i thought "arr" was the pointer array..?

There's no 2d arrays in cpp, only array of arrays

i thought "arr" was the pointer array..?

okay, first of all any array is just a pointer, so when u create int arr[10]; u just create int *arr; which points to the area with size of sizeof(int) * 10;

of course its different but it is even worse then

Yes

I already said I can

Pls send me code

sounds like a nice business

With vector of vectors u can create only nxn matrix

If I get paid, I can do someone's homework no problem

but no one is offering money and also tey are asking to have a solution urgently

There's no 2d arrays in cpp, only array of arrays

but we can access a[i][j] right?

but no one is offering money and also tey are asking to have a solution urgently

And that's why I'm not going to even bother

but we can access a[i][j] right?

+

but we can access a[i][j] right?

Yes, i - ur pointer array, j - element of yours array

Pls send me code

Stop it already