-Og enables optimizations that do not interfere with debugging

wtf is if(i=(2,1,0))?

*Today's question* Q)What will be output of the following question #include <stdio.h> int main() { int i; if(i=(2,1,0)) printf("welcome "); else printf("Hello "); printf("%d\n",i); } a)Hello 3 b)welcome 0 c)Hello 0 d)welcome 3 Hey everyone . I have a doubt in this question . I know precedence of paranthesis is greater than that of equality ,and associativity of paranthesis is from left to right .. that's y 0 gets stored in i. But since 0 is simply assigned in i , how does this makes if condition false?

If condition ...

i=0 is false, because it returns 0, and 0 is the only integral that casts to false

can you explain what exactly happens there, why there are 2,1,0?

because I don't remember ever seeing such syntax

i= 0 means assignment of 0 in a variable named i. Is int i=0; if i Same as int i=0;

Comma operator

*Today's question* Q)What will be output of the following question #include <stdio.h> int main() { int i; if(i=(2,1,0)) printf("welcome "); else printf("Hello "); printf("%d\n",i); } a)Hello 3 b)welcome 0 c)Hello 0 d)welcome 3 Hey everyone . I have a doubt in this question . I know precedence of paranthesis is greater than that of equality ,and associativity of paranthesis is from left to right .. that's y 0 gets stored in i. But since 0 is simply assigned in i , how does this makes if condition false?

So what is if(i=(1,2,0)) ?

*Today's question* Q)What will be output of the following question #include <stdio.h> int main() { int i; if(i=(2,1,0)) printf("welcome "); else printf("Hello "); printf("%d\n",i); } a)Hello 3 b)welcome 0 c)Hello 0 d)welcome 3 Hey everyone . I have a doubt in this question . I know precedence of paranthesis is greater than that of equality ,and associativity of paranthesis is from left to right .. that's y 0 gets stored in i. But since 0 is simply assigned in i , how does this makes if condition false?

Do you send these type of questions daily?

The answer is C

No...I get these questions in my uni's coding club group ... I was having a doubt today

so it's like "execute and forget about it"? in this case 2 and 1 will be just skipped?

Pretty much that's it

If Statement

The comma operator returns the last operand. It's been used for a lot of (doubtful) things. It even led to some library implementors to think about it's overloading (yes, you can overload the comma operator)

I know that it's an if statement but what does it evaluates to?

I tried to explain it earlier So (2,1,0) returns zero i=0 returns zero if(0) evaluates as false And you got Hello from that branch

How does it work

I tried to explain it earlier So (2,1,0) returns zero i=0 returns zero if(0) evaluates as false And you got Hello from that branch

3 params in one parantheis

3 params in one parantheis

I know that pretty well. I was asking for the explanation I guess

If statement gets executed only when it gets its condition true(i.e 1 ) so by initialisation i =1, the if statement will be executed ....if u assign any other value then non zero value it will get executed ...but when u assign 0 ...it gets false

Its comma operator... Google it

**Any value except than zero is true

++n is first evaluate although its result is discarded

what after that

how is m getting calculated

https://www.google.com/amp/s/www.geeksforgeeks.org/comna-in-c-and-c/amp/

bcz

So, im right?

https://www.spoj.com/problems/BSEARCH1/ Can somebody help me with uploading this problem's solution in spoj. I am fairly new in competitive programming .In this binary search problem my code is running fine, outside in my local compiler but I am unable to know why my code is not accepted by the spoj. Help me out. Here is my code: #include <bits/stdc++.h> using namespace std; int arr[100],numberOfElemenets; int BinarySearch(int x){ int mid,left=0,right=numberOfElemenets; while(left<=right){ mid=(left+right)/2; if(arr[mid]==x) return mid; else if (arr[mid]>x) right = mid-1; else left = mid +1; } return -1; } int main() { int n; cout<<"Enter the number of elements: "; cin >> n; for(int i=0 ; i<n ; ++i){ cin>>arr[i]; } for(int i=0 ; i<n ; ++i){ cout<<arr[i]<<" "; } cout<< endl; cout<<"The elements is present at :"<<BinarySearch(2)<<endl; cout<<"The elements is present at :"<<BinarySearch(4)<<endl; cout<<"The elements is present at :"<<BinarySearch(8)<<endl; }

7 6 1

It shud be in otherway ig

is my ans correct if printf is used instead of cout

is my ans correct if printf is used instead of cout