这个可以吗
this is the real why
BinaryByter
Ariana
想要死了
Ariana
jk
BinaryByter
in one sentence
Ariana
XD
BinaryByter
😂
Anonymous
you know it, you prolly overread it ¯\_(ツ)_/¯
you said that a%b can't be higher than b
BinaryByter
Now chinese slave, tell me how PCM waves work and i'll give you a bit of my food 😂
Anonymous
but you never told why it is that way
BinaryByter
but you never told why it is that way
% is a way to get how much is left over when dividing in N
Anonymous
i
Anonymous
know
Anonymous
so?
BinaryByter
1 % 7 = 1
2 % 7 = 2
3 % 7 = 3
4 % 7 = 4
5 % 7 = 5
6 % 7 = 7
7 % 7 = 0
Anonymous
there is nothing left over if the number fits perfectly
the problem is when it doesn't
BinaryByter
the problem is when it doesn't
you can only have 6 numbers too many at once if you divide by 7
Anonymous
how do i check if 2348723647547823%30 is <30?
Mihail
but you never told why it is that way
Well you know how you could didvide a / b by just subtracting b from a while a > b, so you're guaranteed that the remainder will be a number < a
Ariana
0%17+29 = 29
1%17+29 = 30
2%17+29 = 31
3%17+29 = 32
4%17+29 = 33
5%17+29 = 34
6%17+29 = 35
7%17+29 = 36
8%17+29 = 37
9%17+29 = 38
10%17+29 = 39
11%17+29 = 40
12%17+29 = 41
13%17+29 = 42
14%17+29 = 43
15%17+29 = 44
16%17+29 = 45
17%17+29 = 29
18%17+29 = 30
19%17+29 = 31
20%17+29 = 32
21%17+29 = 33
22%17+29 = 34
23%17+29 = 35
24%17+29 = 36
25%17+29 = 37
26%17+29 = 38
27%17+29 = 39
28%17+29 = 40
29%17+29 = 41
30%17+29 = 42
31%17+29 = 43
32%17+29 = 44
33%17+29 = 45
34%17+29 = 29
35%17+29 = 30
36%17+29 = 31
37%17+29 = 32
38%17+29 = 33
39%17+29 = 34
40%17+29 = 35
41%17+29 = 36
42%17+29 = 37
43%17+29 = 38
44%17+29 = 39
45%17+29 = 40
46%17+29 = 41
47%17+29 = 42
48%17+29 = 43
49%17+29 = 44
50%17+29 = 45
51%17+29 = 29
52%17+29 = 30
53%17+29 = 31
54%17+29 = 32
55%17+29 = 33
56%17+29 = 34
57%17+29 = 35
58%17+29 = 36
59%17+29 = 37
60%17+29 = 38
61%17+29 = 39
62%17+29 = 40
63%17+29 = 41
64%17+29 = 42
65%17+29 = 43
66%17+29 = 44
67%17+29 = 45
68%17+29 = 29
69%17+29 = 30
70%17+29 = 31
71%17+29 = 32
72%17+29 = 33
73%17+29 = 34
74%17+29 = 35
75%17+29 = 36
76%17+29 = 37
77%17+29 = 38
78%17+29 = 39
79%17+29 = 40
80%17+29 = 41
81%17+29 = 42
82%17+29 = 43
83%17+29 = 44
84%17+29 = 45
85%17+29 = 29
86%17+29 = 30
87%17+29 = 31
88%17+29 = 32
89%17+29 = 33
90%17+29 = 34
91%17+29 = 35
92%17+29 = 36
93%17+29 = 37
94%17+29 = 38
95%17+29 = 39
96%17+29 = 40
97%17+29 = 41
98%17+29 = 42
99%17+29 = 43
Ariana
have fun XD
BinaryByter
I only accept C++
Mihail
So will it be less than 30?
Anonymous
that's one easy way to think of it
Anonymous
thank you!
Mihail
No problem
Ariana
31%17+29 = 14+29 = 43
32%17+29 = 15+29 = 44
33%17+29 = 16+29 = 45
34%17+29 = 0+29 = 29
35%17+29 = 1+29 = 30
36%17+29 = 2+29 = 31
37%17+29 = 3+29 = 32
38%17+29 = 4+29 = 33
39%17+29 = 5+29 = 34
40%17+29 = 6+29 = 35
41%17+29 = 7+29 = 36
42%17+29 = 8+29 = 37
43%17+29 = 9+29 = 38
44%17+29 = 10+29 = 39
45%17+29 = 11+29 = 40
46%17+29 = 12+29 = 41
47%17+29 = 13+29 = 42
48%17+29 = 14+29 = 43
49%17+29 = 15+29 = 44
50%17+29 = 16+29 = 45
51%17+29 = 0+29 = 29
52%17+29 = 1+29 = 30
53%17+29 = 2+29 = 31
54%17+29 = 3+29 = 32
55%17+29 = 4+29 = 33
56%17+29 = 5+29 = 34
57%17+29 = 6+29 = 35
58%17+29 = 7+29 = 36
59%17+29 = 8+29 = 37
60%17+29 = 9+29 = 38
61%17+29 = 10+29 = 39
62%17+29 = 11+29 = 40
63%17+29 = 12+29 = 41
64%17+29 = 13+29 = 42
65%17+29 = 14+29 = 43
% will always make sure it is less than the modulo
Ariana
i want to eat format strings
Ariana
jk
Mihail
Not sure if I got it right
BinaryByter
you did
Mihail
Yay
BinaryByter
but we dont have a regex bot
BinaryByter
i hate you
Mihail
We could add one there if there isn't already
🐰🐾 سمیه
int const *p;
Here p is of type " const int " or " const int * ", and why?
BinaryByter
why do you think that const int is a possibility?
BinaryByter
I want to hear your reasoning
🐰🐾 سمیه
And doubted that
🐰🐾 سمیه
int const *ptr = &i; /* pointer to integer constant. Here i
is of type "const int", and &i is of
type "const int *". And p is of type
"const int", types are matching no issue */
BinaryByter
BinaryByter
ptr is of type const int * just like &i is
BinaryByter
(i assume that i is of type int or const int)
🐰🐾 سمیه
Ok thanx 🌷🙏
BinaryByter
:D
BinaryByter
Well done on completely missing the question =D
Carlos
I missed the group
Anonymous
Thanks to be here
H̲i̲L̲e̲v̲e̲l̲
Qq
H̲i̲L̲e̲v̲e̲l̲
What is MAX_PATH?
BinaryByter
its MY path
H̲i̲L̲e̲v̲e̲l̲
Thx
H̲i̲L̲e̲v̲e̲l̲
Best help
H̲i̲L̲e̲v̲e̲l̲
Can everyone answer me?)
olli
What is MAX_PATH?
either google it or provide some context. It's nothing that's defined by ISO C/C++.
https://docs.microsoft.com/en-us/windows/desktop/fileio/naming-a-file
Dima
Lol
Shivam
Perfect
AmdeSelassie
Any one knows about web app or links to the web app groups?
Anonymous
Is there a c compiler for android phones
Mihail
Is there a c compiler for android phones
you could try Termux, but even better just use an actual PC
Mihail
a phone just isn't a good idea