Dima
*(&lol)**ptr->cant->hear->you->**all->overThis++;
Daniele°
*(&lol)**ptr->cant->hear->you->**all->overThis++;
Can substitute * with [0]
Daniele°
Daniele°
(&lol)[0].ptr[0].cant[0].blablabla
Ибраги́м
can emulate lambdas with gcc C dialect
#define lambda ({ 0 )}
or other techniques
5. Another reason to hate C: it's all hack-job.
Daniele°
Ибраги́м
can emulate lambdas with gcc C dialect
#define lambda ({ 0 )}
or other techniques
This is what u call lambda?
🐰🐾 سمیه
again *s is char* and **s is char... yes the address of the char(s) are obv the same.
In that program, *s is a pointer that points to the first element of string literal "hello". And **s is a pointer that points to *s which points to the first element of "hello". Correct?
🐰🐾 سمیه
how is that?
BinaryByter
char ** => one pointer points to an array of chars
olli
In that program, *s is a pointer that points to the first element of string literal "hello". And **s is a pointer that points to *s which points to the first element of "hello". Correct?
No *s is char * (the first word)
**s is not a pointer any more, it's char, the first letter
Daniele°
char a;
char* b=&a;
char** c =&b
Daniele°
char*** d=&c
Anonymous
In that program, *s is a pointer that points to the first element of string literal "hello". And **s is a pointer that points to *s which points to the first element of "hello". Correct?
**s points to address of pointer..that points to 'h' in hello
Anonymous
🐰🐾 سمیه
BinaryByter
yes
BinaryByter
thats better
🐰🐾 سمیه
And that makes sense
🐰🐾 سمیه
No *s is char * (the first word)
**s is not a pointer any more, it's char, the first letter
Previously you told me that char ** is a pointer to a pointer to a char, and on internet everyone are saying so. Why you say it's simply a char
Anonymous
yes
Is it possible to enter elements in array by recursion...not by for loop.
I'm just trying to reduce complexity
BinaryByter
Previously you told me that char ** is a pointer to a pointer to a char, and on internet everyone are saying so. Why you say it's simply a char
hes talking about the twice dereferenced s
BinaryByter
he did
Anonymous
No *s is char * (the first word)
**s is not a pointer any more, it's char, the first letter
Bro..it's *s is a pointer..that stores address of element of char type
BinaryByter
No, *s is a once dereffered pointer
Anonymous
No, *s is a once dereffered pointer
You way of explanation is somehow complex..
You don't explain in simple language
olli
If you dereference a pointer to pointer to char once you get a pointer to char
olli
It's as easy as that
olli
If you dereference a pointer to pointer to char twice you get a char
olli
That's all I said
Anonymous
If you dereference a pointer to pointer to char twice you get a char
Okay..just tell me..if I print
**s.
Than what would it print
Anonymous
?
🐰🐾 سمیه
If you dereference a pointer to pointer to char once you get a pointer to char
Please write it by notations
BinaryByter
UB
Not UB in the traditional sense of "undefined by standard" (unless you really never allocate the string) but rather : "now knowable at runtime"
🐰🐾 سمیه
Anonymous
Could be a address or the word "hello"
Bro..
But *s should point to address of first char of string..
olli
Bro..
But *s should point to address of first char of string..
Yes because it's a pointer to char
🐰🐾 سمیه
Yes, and the bigger example from yesterday
char *s[] = { "Hello", "World" };
s defeferences a char (the first letter of the first world => 'H')
*s dereferences a char* (the first word => "Hello")
*(*(s+1)+1) dereferences a char (the second letter of the second word => 'o')
(s+1) dereferences to char ('W')
*(*s+1) dereferences to char ('e')
*(s+1) dereferences to char*("World")
== Ingoring const for simplicity ==
🐰🐾 سمیه
This?
olli
Bro..
But *s should point to address of first char of string..
printf("%p", *s); what does this print?
Anonymous
Wtf..
*s should print whole string..?
Anonymous
Hello
olli
char *s[] = { "Hello", "World" };
**s defeferences a char (the first letter of the first world => 'H')
*s dereferences a char* (the first word => "Hello")
*(*(s+1)+1) dereferences a char (the second letter of the second word => 'o')
**(s+1) dereferences to char ('W')
*(*s+1) dereferences to char ('e')
*(s+1) dereferences to char*("World")
== Ingoring const for simplicity ==
This - copying got rid of stars
char *s[] = { "Hello", "World" };
**s defeferences a char (the first letter of the first world => 'H')
*s dereferences a char* (the first word => "Hello")
*(*(s+1)+1) dereferences a char (the second letter of the second word => 'o')
**(s+1) dereferences to char ('W')
*(*s+1) dereferences to char ('e')
*(s+1) dereferences to char*("World")
== Ingoring const for simplicity ==
Anonymous
?
Anonymous
**s
Anonymous
Means h
Anonymous
I think
Anonymous
But not sure
olli
Yes and that's what I said above (regarding the h part)
olli
no
BinaryByter
/pardon @Landi58
Anonymous
y
BinaryByter
oh that works
BinaryByter
cool
Anonymous
Now...my question is .
How to convert string into char array in C++
BinaryByter
string::c_str()
BinaryByter
next time, use google