no, void is syntactically forced to be put

but actually, I think that main is an inbuilt symbol and doesnt take a return type for that reason

but actually, I think that main is an inbuilt symbol and doesnt take a return type for that reason

you think it should be like: int main?

Hi all

#include<iostream> #include<math.h> #include<iomanip> using namespace std; void maximumBoxVolume(double length,double width,double& maxBoxVolume,double& sqlength); double min1(double,double); int main() { double length[20],width[20],sqlength[40]; double maxBoxVolume[30]; int carboardArea; double values[50]; int k = 0; int i; int count=0; cout<<"Enter the area of the cardboard: "; cin>>carboardArea; for(i=1;i<=carboardArea;i++) { if(carboardArea % i==0) { values[count]=static_cast<double>(i); count++; } } for (i = 0;i<count/2;i++) width[i]=values[i]; int x=count/2; for (int j=count-1;j>=x;j--) { length[k]=values[j]; k++; } for(i=0;i<x;i++) { maximumBoxVolume(length[i],width[i],maxBoxVolume[i],sqlength[i]); } double max=maxBoxVolume[0]; int maxpos; for(int i=1;i<x;i++) { if(maxBoxVolume[i]>max) { max=maxBoxVolume[i]; maxpos=i; } } cout<<"\nLength of the card board = "<<length[maxpos]<<" inches\n"; cout<<"Width of the card board = "<<width[maxpos]<<" inches\n"; cout<<"Length of the square to cut to form a box = "<<setprecision(3)<<sqlength[maxpos]<<"inches\n"; cout<<"Maximum volume of a box = "<<setprecision(3)<<maxBoxVolume[maxpos]<<" cube inches\n"; return 0; } void maximumBoxVolume(double length,double width,double&maxBoxVolume,double& sqlength) { double sqSide; double boxVolume; sqSide=0.001; maxBoxVolume=0.0; double minSide=min1(length,width); while (2*sqSide<=minSide) { boxVolume=sqSide*(length-2*sqSide)*(width-2*sqSide); if(maxBoxVolume<boxVolume) { maxBoxVolume=boxVolume; sqlength=sqSide; } sqSide+=0.001; } } double min1(double 1,double w) { if(1<w) return 1; return w; }

Error : 'w' was not declared in this scope

Sure why not

you think it should be like: int main?

No

What's the problem

Error : 'w' was not declared in this scope

where do you declare w?

Sure why not

😂

where do you declare w?

I thought you were solving my prblem🙁

Where do I know him?

I thought you were solving my prblem🙁

you don't have a problem

+ i can solve multiple problems at once

why there is ( left + right) / 2 in swap here?

this is my question

why there is ( left + right) / 2 in swap here?

first of all, it should be a bitshift but okay

This is the amount of bytes to swap, i assume

swap interchanges elements of array

yes

yes

division is for what?

they only want to swap half of the char* buffer with the other buffer

why there is ( left + right) / 2 in swap here?

oh wait no theres a definition of swap down below

Right, they exchange the element left with the element left + r ight / 2

so the middle between both

(this formula calculates an average)

though they should use ( left + right ) » 2; for performance reasons

for example : if left is 0, which always is, and right is 1, which for the second call of qsort is, then swap becomes : swap( v, 0, 0+1/2=0)

it wont work that way

left doesnt have to be 0

look at main. for the second call of qsort, it'll like what i said

well in the first call, 1/2 will be 0

but then you increase left

read the code instead of asking lol

well in the first call, 1/2 will be 0

that way, for the fisrt and and second line, how they would be sorted?

if the element in the current left is greater than the middle, swap it lol

read the code instead of asking lol

I've done that for times

class A; class B; class B { A test() { A a; return a; } }; class A { B test() { B b; return b; } }; I cannot believe that C++ has so bad design

if the element in the current left is greater than the middle, swap it lol

don't laugh at me 👊

class A; class B; class B { A test() { A a; return a; } }; class A { B test() { B b; return b; } }; I cannot believe that C++ has so bad design

What do you mean?

if the element in the current left is greater than the middle, swap it lol

then, what happens at the seccond call?🤔

error: aggregate 'A a' has incomplete type and cannot be defined A a; ^

it cannot be compiled ... forever

error: aggregate 'A a' has incomplete type and cannot be defined A a; ^

You have to define A before using it

like... You probably have something like class A;

but A; isnt defined

class A; class B; class B { A test() { A a; return a; } }; class A { B test() { B b; return b; } }; I cannot believe that C++ has so bad design

oh here it is

look at my code

You cannot use variables of an undefined type

instead, use pointers

pointers should be fine

then, what happens at the seccond call?🤔

@BinaryByter

but I have to return by VALUE

but I have to return by VALUE

that won't work

you might be able to get away by using inheritance

but no, that will require pointers too

exactly I wrote - I cannot believe that C++ has so bad design

No, what you are doing is bad design

??? I want return by value

what wrong with me?

what wrong with me?

doing such things is awkward

😒

though they should use ( left + right ) » 2; for performance reasons

or use anything more than -O1

lmao

i searched for an infinite loop in my code for half an hour

Guess where it hid 😂

IT FUCKING HID IN THE COMPILATION COMMAND

appearently on clang -O3 means "add an infinite loop at the start of the main function"

I have something befitting for you, my friend

lets see it

oh right gcc even optimizes /2 without -O1

oh right gcc even optimizes /2 without -O1

yep

oh clang too

no

clang doesnt

clang only optimizes with -O1

but other compilers might not optimize that

well then just don't use bitshift and be more expressive

so » can't hurt ¯\_(ツ)_/¯