Anonymous
http://this.is-a-professional-domain.com/AQKNxHN.png
Anonymous
Yep
Anonymous
It jumps back fine
Anonymous
http://this.is-a-professional-domain.com/4A95q9y.png
Anonymous
http://this.is-a-professional-domain.com/7uX1s9w.png
Anonymous
My jump gous back to the push edi
olli
http://this.is-a-professional-domain.com/AQKNxHN.png
do you know the value of esi ? are you sure you can write at that location?
Anonymous
Well im not sure if i can
Anonymous
I can mod original dec esi in cheat engine to like inc esi
Anonymous
But i can't call inc esi in my own dll
olli
But i can't call inc esi in my own dll
but you are not incrementing esi you inrement the location at position esi ?
Anonymous
Hu?
olli
0xc0000005 iirc should be access violation
Anonymous
So my opcode is wrong
olli
inc esi => increase esi inc DWORD PTR [esi] => increase DWORD value at address esi
Anonymous
I know that its a DWORD val
Anonymous
http://this.is-a-professional-domain.com/5Qp3bjX.png
Anonymous
Thats the original instruction
Anonymous
inc esi dous not crash the exe but ain't making any noticable changes
Anonymous
http://this.is-a-professional-domain.com/8JiEGJe.png
Anonymous
What does LSB mean if it's -1 ?
Anonymous
is it second bit then ?
Anonymous
🐰🐾 سمیه
Hi, would you pleease explain me how this function works?
klimi
Hi, would you pleease explain me how this function works?
are you really sure you cant do it on your own?
🐰🐾 سمیه
yep
klimi
yep
and you cant transfer it into pseudo code?
🐰🐾 سمیه
its passage is here
🐰🐾 سمیه
klimi
int a = 5; pseudo: variable a equals 5
Daniele°
its passage is here
n%10 return one number '0'+n%10 return ASCII rappresentation of number
Daniele°
n/10 get next number
Daniele°
Example 10%10 = 0 10/10=1 1%10=1
🐰🐾 سمیه
First if print - if Is < 0
After that why -n is assigned to n?
🐰🐾 سمیه
For remove sign
Why it'll be removed after assignment?
Ибраги́м
its passage is here
aH, STILL on it
Ибраги́м
Good luck
Daniele°
//if Is negative if(n<0){ //Write sign putchar('-'); //Remove sign n=-n; }
Daniele°
n=-2; n=--2==2
🐰🐾 سمیه
Is it 10%1 or 1%10?
🐰🐾 سمیه
Hi, would you pleease explain me how this function works?
Daniele°
Hi, would you pleease explain me how this function works?
1234%10=4 1234/10=123 123%10=3 123/10=12 12%10=2 12/10=1 1%10=1 1/10=0 end
🐰🐾 سمیه
1%10
But we can't divide 1 by 10 and get the remainder.
🐰🐾 سمیه
aH, STILL on it
Don't distract please 🙏
Daniele°
Hi, would you pleease explain me how this function works?
This works only for numbers from 0 to 99
🐰🐾 سمیه
Let me think please.
Daniele°
Uh is recursive
Daniele°
Works with all numbers
Daniele°
recall printd every time n/10 > 0
Daniele°
if n>9 call printd
🐰🐾 سمیه
🐰🐾 سمیه
Why the reminder of 1%10 becomes zero?
Daniele°
😳
Daniele°
1/10=0
🐰🐾 سمیه
😳
What's wrong? 😶
Anonymous
What's wrong? 😶
we dont divide like this
🐰🐾 سمیه
1 is not dividable by 10, thus I put a zero
Daniele°
🐰🐾 سمیه
Anonymous
What's wrong? 😶
just a different notation but the division is right
🐰🐾 سمیه
Not understand
Sorry, numbers were persian
Daniele°
klimi
o.o
Daniele°
😂
Anonymous
Sorry, numbers were persian
yes and the way you did the division is also persion
🐰🐾 سمیه
Anonymous
Guys this is correct just different notation
Daniele°
1|10 -|-- 1|0
Right Number Is 1/10 Left number Is 1%10
🐰🐾 سمیه
Daniele°
12/10 Left Number Is 12%10=2 Right Is 12/10=1