olli
it always depends on the type what actually happens when moved from. for std::unique_ptr for example the standard describes the behavior.
BinaryByter
Oh
MᏫᎻᎯᎷᎷᎬᎠ
Thank you again lol
olli
sure :)
A45h1
Do any one know what is carding
Mat
Do any one know what is carding
A little ddg search told me what it is
A45h1
Any context?
Do you know
A45h1
Wat is it
A45h1
?
Liam
Wat is it
Faint... CARDING is a single word and has many meaning. What it is depends on the context of the word. Who, in God's name, knows what it is without any context?
A45h1
Oh
Liam
Mind OS: "I have a warn and a ban, which one do you prefer more?"
Dima
Dima
k sorry I will not do this anymore
S.
https://en.wikipedia.org/wiki/Carding_(fraud)
S.
So … that carding guy is out?
Mat
Which pleasure?
Liam
So … that carding guy is out?
That's why my inner mind OS..
Mat
It's not a pleasure
Anonymous
Hi
Hakker
plz help
Hakker
how to check frequency of a number in input number
Hakker
without arrays
Hakker
like if i enter 22313, it should tell that how many 0,1,2... are present
Anonymous
Use while with %10
Anonymous
And remember frequency
MᏫᎻᎯᎷᎷᎬᎠ
without arrays
Use std::vector then xD
爱月夜眠迟
unordered_map
Liam
std::cin >> s directly would be better.
Liam
/ban discrimination words.
Dima
lol lmao
klimi
@LiamHuang was it that bad?
Roxifλsz 🇱🇹
@LiamHuang was it that bad?
It was a quote of Terry Davis
Roxifλsz 🇱🇹
Dima
God save us ... https://github.com/Wittmaxi/Maxix
Dima
Liam
@LiamHuang was it that bad?
You mean the N-word?
Dima
do you have n-word pass?
Anonymous
Indians are more powerful because they already have n word pass
Liam
Yes
Well, I'll reply this in the admin group.
Kanchan
Hi
MᏫᎻᎯᎷᎷᎬᎠ
Hi
Kanchan
I want c programming interview questions
Dima
cool
Dima
Dima
#ot
MᏫᎻᎯᎷᎷᎬᎠ
Yeah
Dima
Indians: reach superpass for n-word by 2020
BinaryByter
xDD
Dima
stop it right here
mark
Roxifλsz 🇱🇹
So it was bad?
Kek, I'm completely indifferent to whether it's bad or not, it wasn't an ad or a homework request so I'm fine with it :D
Dima
you are officially equipped with the N-word pass
Anonymous
Can we find subarray with time complexity less then O(n^3)
BinaryByter
you mean a string compare?
BinaryByter
yes
BinaryByter
you can do string comparisons in O(n * m)
Anonymous
No buddy I want find sub array of e.g.[1,2,3] in time complexity of O(n3)
BinaryByter
sub array=?
Mihail
sub array=?
Find 12 in 123 I guess
BinaryByter
Anonymous
BinaryByter
Find 12 in 123 I guess
thats a string search
BinaryByter
which you do in O n*m
Mihail
Yeah
BinaryByter
If you do your string searches in n cubed, you have brain cancer
Mihail
I don't know how to do it in n^3 tbh
yuuki
Totally unrelated. In c sharp, we have these jagged arrays, right? Can there be 3 dimensional ones too? Like string[] [] [] v_space