You can start with #include<stdio.h> for c
#include<iostream.h> for c++
#include <iostream> without .h
Mihail
Anonymous
Linklist
Hakker
👍👍
Anonymous
BinaryByter
Tomorrow is my exam on C++ . Please provide me videos and links that will help me to score good marks .
If you have coded enough in your free time, you'll pass
BinaryByter
else, you can try to code some test exercises
Anonymous
Tomorrow is my exam on C++ . Please provide me videos and links that will help me to score good marks .
Good luck with that one :) The video material only will take longer than one day. Hope you have already made some solid knowledge
Anonymous
How can I minimize stack overflow condition?
BinaryByter
you put less stuff ontp the stack
BinaryByter
Nope
BinaryByter
buy yourself a bigger stack
Anonymous
buy yourself a bigger stack
This will result in expensive use of space if there are few elements in stack
BinaryByter
kek'd
Bruce
#include<stdio.h>
int main()
{int T,N,i,f,l;
scanf("%d",&T);
int a[T],b[T];
for(i=0;i<T;i++)
{scanf("%d",&N);
a[i]=N;
}
for(i=0;i<T;i++)
{f=a[i]%10;
if(a[i]/10==0)
{l=0;}
else
{
while (a[i]>10)
{l=a[i]/10;
a[i]=a[i]/10;}}
b[i]=f+l;}
for(i=0;i<T;i++)
{printf("%d\n",b[i]);
}
}
The above program is to print the sum of first and last digit of given input number,for given input test cases
I did get my out put correct for my input,but in an online contest it showed wrong ans ,are there any cases where it fails
Bruce
At least format it
#include<stdio.h>
int main()
{
int T,N,i,f,l;
scanf("%d",&T);
int a[T],b[T];
for(i=0;i<T;i++)
{
scanf("%d",&N);
a[i]=N;
}
for(i=0;i<T;i++)
{
f=a[i]%10;
if(a[i]/10==0)
{l=0;}
else
{
while (a[i]>10)
{l=a[i]/10;
a[i]=a[i]/10;
}
}
b[i]=f+l;
}
for(i=0;i<T;i++)
{printf("%d\n",b[i]);
}
}
Now is it ok?
Bruce
The above program is to print the sum of first and last digit of given input number,for given input test cases
I did get my out put correct for my input,but in an online contest it showed wrong ans ,are there any cases where it fails
Gianmarco
Hi guys, i ve a question: i tried to create a little program in C for train myself for the test. If i run the project through my IDE it works like a charm, when i run It through the compiled .exe It doesnt work anymore
S.
Gianmarco
My program writes on a file "password.txt", when i run from IDE the file .txt its created, when i run from .exe It creates a file named "filename" 0kb
klimi
Weird indeed
Gianmarco
I tried with 2 different IDE but with same results
S.
What's the path you wrote for fopen
S.
( show the code please
Parra
Gianmarco
Ok i have It on my desktop PC, i have to upload It online?
S.
Ok i have It on my desktop PC, i have to upload It online?
No necessarily but only with this info it's difficult to guess the problem
Gianmarco
https://pastebin.com/VtVLQ5uz
S.
fp = fopen("fileName", "a");
if((fp = fopen(fileName, "a")) == NULL) {
printf("errore in apertura!\n");
exit(1);
}
S.
Look at this carefully
S.
"fileName" vs. fileName
Gianmarco
Oh...
Gianmarco
I m checking
Gianmarco
I deleted the " " in filename
Gianmarco
But now It doesnt create anything
olli
Output must be 1 bt according to code it is coming 0
Exactly (actually it's undefined because you never set l in this case)
Anonymous
#include<stdio.h>
int main()
{
int T,N,i,f,l;
scanf("%d",&T);
int a[T],b[T];
for(i=0;i<T;i++)
{
scanf("%d",&N);
a[i]=N;
}
for(i=0;i<T;i++)
{
f=a[i]%10;
if(a[i]/10==0)
{l=0;}
else
{
while (a[i]>10)
{l=a[i]/10;
a[i]=a[i]/10;
}
}
b[i]=f+l;
}
for(i=0;i<T;i++)
{printf("%d\n",b[i]);
}
}
Now is it ok?
For numbers in powers of 10, the code is giving incorrect output.
MᏫᎻᎯᎷᎷᎬᎠ
Exactly (actually it's undefined because you never set l in this case)
Olliiii
What up :D
Gianmarco
guys if i have my .exe how can i make it execute a part of code only the first time it opens?
olli
Olliiii
What up :D
Hey! getting ready for work and reading the core coroutine proposal (again) :D
You?
MᏫᎻᎯᎷᎷᎬᎠ
Hey! getting ready for work and reading the core coroutine proposal (again) :D
You?
Wow seems awesome
I'm just good :D
MᏫᎻᎯᎷᎷᎬᎠ
Maybe lol
Gianmarco
CM
Anonymous
maybe if you can tell your intention on this program
I think the condition is while loop through which the last digit of the number is obtained is incorrect
It should be:-- while(a[i] >1)
CM
I think there is something not declared there because its giving one answer for all values
Mat
Dima
welcom
Alex
cout « "Thanks everyone"
klimi
Welcome
Shreyash
Hii
klimi
Hi
MᏫᎻᎯᎷᎷᎬᎠ
Hi
klimi
Welcome
Gokul Rangaraju
Hai
klimi
Hi
Hakker
how to setup jetbrains clion
Dima
LOL
Hakker
i'm unable to compile, i have installed compiler
Hakker
w8 i show u error
MᏫᎻᎯᎷᎷᎬᎠ
Okay