@programminginc - страница 1214

Anonymous

however he forgot to allocate memory first

Thats what I said

BinaryByter

Your statement was too general to be helpfuö ;)

Anonymous

Your statement was too general to be helpfuö ;)

Yeah right.. I thought he knew it

Anonymous

Well, string is fun with C anyway

Anonymous

:D

BinaryByter

YEAAA

BinaryByter

very fun...

BinaryByter

xD

Anonymous

xD

😂

Anonymous

C strings: Hello Mr Conor, How wou5d y0u l1ck 2 j(^jf;a35740-DJ)_98_*^#(D($^)_97)_$&()_(V)($(0=(&_$(_)V$&(_*Y_(SF*_*%Y_*FY(W*Y

itsmanjeet

For string i mainly use Array Never use pointer or allocation sprintf for strcat strcpy etc But when i reuse the same array It give segment fault

itsmanjeet

Anonymous

For string i mainly use Array Never use pointer or allocation sprintf for strcat strcpy etc But when i reuse the same array It give segment fault

Anonymous

Eh ehe eh.. still no malloc or any sort of allocation

itsmanjeet

Eh ehe eh.. still no malloc or any sort of allocation

😔😞 Sry i am still a learner never used malloc much And never for string

Anonymous

😔😞 Sry i am still a learner never used malloc much And never for string

Ok, do you need a guide?

itsmanjeet

Ok, do you need a guide?

Yes

Anonymous

Yes

There you go: https://www.tutorialspoint.com/c_standard_library/c_function_malloc.htm

itsmanjeet

There you go: https://www.tutorialspoint.com/c_standard_library/c_function_malloc.htm

Thanks

Luis José

man string[] is not same as char *string

What are those differences?

🐰🐾 سمیه

Hi, Would you please explain this part?

Anonymous

What are those differences?

Not really different. I meant generally one use the expression (*string)++ to change the value that ptr points to when string is a pointer and not an array..

BinaryByter

What are those differences?

The compiler wievs them as two types + with [] you can define a size to be preallocated

Luis José

Thanks guys!!

MᏫᎻᎯᎷᎷᎬᎠ

.

Ибраги́м

..

Ludovic 'Archivist'

if we cant have goto, we lose the ability to create state automata

That is false, in fact the advised way to make a state automata is to hold an accessor to the function of the current state and call it

klimi

Welcome

Dima

top kek

Anonymous

This compiles , but when I Type in the inputs it not working

Ибраги́м

Use this link instead: https://pastebin.com/i7ad1r0M

Ибраги́м

USe pastebin for long codes

Anonymous

https://pastebin.com/i7ad1r0M

Anonymous

Use this link instead: https://pastebin.com/i7ad1r0M

Copy

Ибраги́м

Thank you!

Ибраги́м

This compiles , but when I Type in the inputs it not working

Ok, there lots of problems with thy code.

Anonymous

Ok, there lots of problems with thy code.

I see

Anonymous

Ok, there lots of problems with thy code.

Can you specify

Ибраги́м

Can you specify

Oh yeah I will.

Anonymous

Oh yeah I will.

You would also need a text file in the same directory with the same name

Anonymous

Oh yeah I will.

Hey

Ибраги́м

1. char inputfunction(); void outputloop(char x); void mainloop(); is NOT needed, just define and use them. 2. std::endl is evil in this case, learn more here: - https://www.youtube.com/watch?v=GMqQOEZYVJQ - https://www.youtube.com/watch?v=6WeEMlmrfOI 3. Your conditional statements are another source of nemesis. if(x = 'A') should be if(x == 'A') and same goes for the rest.

Anonymous

1. char inputfunction(); void outputloop(char x); void mainloop(); is NOT needed, just define and use them. 2. std::endl is evil in this case, learn more here: - https://www.youtube.com/watch?v=GMqQOEZYVJQ - https://www.youtube.com/watch?v=6WeEMlmrfOI 3. Your conditional statements are another source of nemesis. if(x = 'A') should be if(x == 'A') and same goes for the rest.

Thought you have to prototype your functions

Ибраги́м

You thought wrong

Anonymous

You thought wrong

Lol

Ибраги́м

4. outputloop('Q'); break; theirchoice = inputfunction(); This will never be executed 'cos u have a break before that already in: case 4: outputloop('D'); break;

Anonymous

4. outputloop('Q'); break; theirchoice = inputfunction(); This will never be executed 'cos u have a break before that already in: case 4: outputloop('D'); break;

O yea, suppose to be case 5

Ибраги́м

4. outputloop('Q'); break; theirchoice = inputfunction(); This will never be executed 'cos u have a break before that already in: case 4: outputloop('D'); break;

https://pastebin.com/7AEatDYS

Ибраги́м

O yea, suppose to be case 5

/slap

Ибраги́м

O yea, suppose to be case 5

Next time turn on all warnings... in Debug mode so you can hear all your bell and whistles