ooh i think i understood

so a it's like a counter

right?

Wait, now that i think of it it might just not work with 2 variables

Wait a second

take ur time

Ok, we need to do that with 3 variables

i'm actually doing in while loop : s=a+b; / sum=s+(i want to put here like "Prev", but i don't know how to insert the previous number in inputs)

sum += s

0-0

Ok, we need to do that with 3 variables

a,b and?

a,b and?

I'm thinking about how to do that

What do you actually want to do?

He wants to print the fibonacci sequence from 1 to n

i want to find a way to have a "Previous number" variable

Not sure what n is

its 4 milion

i want to find a way to have a "Previous number" variable

and i think i got that, by doing a= a+b, but then b would be everytime 1, and it needs to change ( i did a=2; and b=1;)

i have to do the sum between the 1st and 2nd number, the 2nd and 3rd, 3rd and 4th

a = 0 b = 1 b = a+b a = b - a

a = 0 b = 1 b = a+b a = b - a

Sum is in b

^^

Sum is in b

Good job

Sum is in b

i should do a=1 and b=2? i have to start from 1 and 2

Sum is in b

Your choice Just don't put 0 in both lol

b = sum of two numbers a = previous number After one iteration of the loop. Loop it the number of times you want

oh so is it with "for"? or i can do it with while?

oh so is it with "for"? or i can do it with while?

With any loop e.e

i mean, my loop right now is: while (b<=4000000)

So basically you want to add numbers till the sum reaches 4M!

?

yeah and i have to see them in the output

i should put the cout in the loop, right?

<<cout<<b;

Ye

i mean cout<< xD

not <<cout

i failed

a = 0 b = 1 --- loop start --- b = a+b a = b-a cout << the thing you wanna print -- end loop--

^

could you explain me the a = b-a code?

It's MATHS uwu

ahah

so if a=5 b=7; b=5+7=13 and a= 7-5=2, how could 2 be the previous number ahah

It's MATHS uwu

UwU

The numbers are attached, how can i fix that?

a = 13 - 5 What the heck

-.-

B is updated dub

oh right

Duh

a= b-a comes after the b= a+b

ur right

i'm a monkey ahah

cout<< b ; this is actually my output code, but the numbers are attached

how can i fix it?

xD

so if a=5 b=7; b=5+7=13 and a= 7-5=2, how could 2 be the previous number ahah

5+7 is 12 not 13

lmao

i'm just tilted from the coding, i'm not that bad ahah dw

xD just jk

cout<< b ; this is actually my output code, but the numbers are attached

Cout<<"\n"<<b?

Or cout<<b<<endl

i don't want to use endl

i don't want to use endl

Spaces?

i want to have every number next to it

exactly

Just use a single space in between

i want to have every number next to it

Cout<<" "<<b;

?

Ye

oh right, "" empty string

oh right, "" empty string

Nu it's a string with a whitespace character ^^

oh haha

i actually have a problem with this program

it gets to 3.5 millions then it sums again

and gets over 4 millions

then it stops

Because b is less than 4 million

As you requested

because the loop sums till B its 4 millions

i mean, it's not a problem, regarding to the exercise, right?