I'm on 1.5 😁😁😁

I'm on cocaine

And I'm Heroine..😁😁😁

And I'm Heroine..😁😁😁

Why..?

Now it has to be 12

what the...

Who make you admin

I think u r also noob like me..

#include <iostream> using namespace std;    class student { private:     int roll; public:     // constructor     student(int r):roll(r) {}        // A const function that changes roll with the help of const_cast     void fun() const     {         ( const_cast <student*> (this) )->roll = 5;     }        int getRoll()  { return roll; } };    int main(void) {     student s(3);     cout << "Old roll number: " << s.getRoll() << endl;        s.fun();        cout << "New roll number: " << s.getRoll() << endl;        return 0; }

This you just copied from geeksforgeeks.. I already checked it..and I don't understand... That's why I asked here

int a = const_cast<int &>(j); a = 12; std::cout << a; *burns in the hell*

int a = const_cast<int &>(j); a = 12; std::cout << a; *burns in the hell*

But ..I just want to change value of j without assigning it to another variable

int a = const_cast<int &>(j); a = 12; std::cout << a; *burns in the hell*

do you know group for begginers

I have better solution of this . std::cout<<*(&j)+7;

Lol, but that doesn't change j

top kek

This? ¯\_(ツ)_/¯

?

Yes... j is stored in ROM.. So it's read-only variable..

This group

Okey.. Is it true..👇👇 const int i= rand();

I'm not a programmer

Sometimes I'm that confused by beginner questions, cause I don't even can determine what they maybe mean... xD

Sometimes I'm that confused by beginner questions, cause I don't even can determine what they maybe mean... xD

I know..I'm begginer.. But instead of writing that much..you just can answer my question in one or two lines.. Isn't it..?

Then how you know that compile time and run time parameters..?

Well, I would, if I would understand what do you want from us