I supose that's the problem.

??

mmm I mean the engine fails even in localhost

Which database are you using

???

But we made some changes

And it already works in localhost.

Which database...?

Which database...?

Azure SQL

If anyone has used cookiecutter-django what's the best way to change project name and domain. I built a project template named "web" with cookiecutter-django that I want to reuse in multiple projects. Now I want to copy it to different repo with different project name and domain. Right now my website name is the project-slug I used. Is changing html template enough or what else I have to change?

how do i can access my list from database to my base.html

any one is there

just pass the object to the template that extend base.html

you can use it on base.html normaly

how do i can access my list from database to my base.html

You have to request that list from the database. list = Model1.objects.all() And then send in the context to the template

just take care and validate if the object exist, if you don't do it you gonna have problems in other views

You have to request that list from the database. list = Model1.objects.all() And then send in the context to the template

this is how to pass the object thanks Emilio!

You have to request that list from the database. list = Model1.objects.all() And then send in the context to the template

then how to iterate it on base.html

then how to iterate it on base.html

With the tags {% for var in list %} <p>{{ var }}</p> {% endfor %}

all right let me try this

Hello everybody. Help me to solve the following problem, please: I have a queryset SomeModel.objects.filter(~Q(info=None)).order_by('-upd')[:num] , but when I try to access fields from there, many fields are empty (even which are not null by the database definition). All works fine if I do .values() on the queryset, but then I have dicts, not objects (which is more comfortable to deal with (IDE suggestions)). I think I need to fetch all fields explicitly from the database. But I dont know how to do it.

Hi. To existing project need to add new field to Permission from django.contrib.auth.models. I find add_to_class, but don't know how to save it. I need to filter values by new field(integer). Can I save add_to_class or any suggestions?

Hi. To existing project need to add new field to Permission from django.contrib.auth.models. I find add_to_class, but don't know how to save it. I need to filter values by new field(integer). Can I save add_to_class or any suggestions?

do you want to override django.contrib.auth.models.Permissions class? this is not good idea, you can create your own class for permissions like class MyP(Permissions) and add all what you want, but then you should rewrite your code which uses the Permissions. Also you can use descriptors

I just need a field to filter by it permissions. I decided to add new class with this field and with FK to Permission model. So i can add permssions there, filter by this field and continue using Permission model

Hi everyone, how can I ensure that when i create a table with a model, all the values are created in the table? https://pastebin.com/zYqkdAVg I would have all status inside the table when i create it

I just need a field to filter by it permissions. I decided to add new class with this field and with FK to Permission model. So i can add permssions there, filter by this field and continue using Permission model

maybe this will be useful https://stackoverflow.com/questions/1876424/add-a-custom-permission-to-a-user

Hi everyone, how can I ensure that when i create a table with a model, all the values are created in the table? https://pastebin.com/zYqkdAVg I would have all status inside the table when i create it

check your migration file

check your migration file

I know i can make it in a migration, but can i do it automatically without having to create again the manual migration if I reset all the migrations?

maybe this will be useful https://stackoverflow.com/questions/1876424/add-a-custom-permission-to-a-user

this is not what i'm talking about. i need field to Permission model to filter permissions like with content type id

I know i can make it in a migration, but can i do it automatically without having to create again the manual migration if I reset all the migrations?

if you want to save your choices in db, you should create new model, and create ForeignKey field in your current model to new one, and create the initial_data.json to fill the new table

if you want to save your choices in db, you should create new model, and create ForeignKey field in your current model to new one, and create the initial_data.json to fill the new table

What i want to do is to do this automatically, without having to execute other files or migrations Does exist an event when a table is created?

can i use another app model within other app templet

What i want to do is to do this automatically, without having to execute other files or migrations Does exist an event when a table is created?

no( https://stackoverflow.com/questions/27808486/automatically-load-django-fixture

no( https://stackoverflow.com/questions/27808486/automatically-load-django-fixture

Ok, thanks

can i use another app model within other app templet

yes, if you provide your.model in your another.app.view

how

like 1_app.models import model_name(in 2_app)

like tis

from app1.models import MyModel

from home.models import SecondaryMenuHome

exactly

def index(request): sec_menu = SecondaryMenuHome.objects.all() for item in sec_menu:

yep

but is not woking

you should return the httpresponse with context

how

?? cant get

i want do some thing like this

foo_list = models.Foo.objects.all() for foo in foo_list: foo.non_db_property = some_method() render_to_response('template.html', {'foo_list': foo_list})

but for seme change there is my model

try

return render(request, template, content)

from django.shortcuts import render

where content is your dict

but your code looks ok

non_db_property?

you can use something like content =my_list = [{'model':x,'property':'123'}for x in UserProfiles.objects.all()]

and you will have list of dicts

just change '123' to your some_method()

in template: {% for c in content%} {{c.model.your_field}} {{c.property}} {%endfor%}

{% for key, value in choices.items %} <li>{{key}} - {{value}}</li> {% endfor %}

>>> Models.objects.filter(id=55)[0].id 0 >>> Models.objects.filter(id=55).values()[0]['id'] 55 Someone explain me this please. I cannot understand...

if i only want to create api

is flask better or django ?

No

is flask better or django ?

GraphQL

Hello

With reference to the documentation, https://www.django-rest-framework.org/api-guide/authentication/#how-authentication-is-determined I was trying to use CustomAuthToken, in my app view and import it in url

But it giving circular import error

my project without customAuth - https://github.com/shubham1507/school/blob/master/users/views.py

from rest_framework.authtoken.views import ObtainAuthToken from rest_framework.authtoken.models import Token from rest_framework.response import Response class CustomAuthToken(ObtainAuthToken): def post(self, request, *args, **kwargs): serializer = self.serializer_class(data=request.data, context={'request': request}) serializer.is_valid(raise_exception=True) user = serializer.validated_data['user'] token, created = Token.objects.get_or_create(user=user) return Response({ 'token': token.key, 'user_id': user.pk, 'email': user.email })

Anyone know how to update the is_confirmed element in serailizer

GraphQL

? You are a bit confused

Any knows how to implement connection pooling in Sqlalchemy ?

has anyone used django-shop ?

how is it

has anyone used django-shop ?

Have a look at Saleor

Have a look at Saleor

i only want to work on api

i only want to work on api

ok, so Saleor GraphQL APIs are still in beta

How to connect multiple database in django