Hi All, Can someone tell me how to use pgbouncer in DRF?

hi what is between status =200 and status= status .HTTP_200_ok in django rest framework ?

hi what is between status =200 and status= status .HTTP_200_ok in django rest framework ?

what do you mean by saying "between" them?

I mean, what is the difference between them?

Is just a constant with the same value

So there is no need to enter this code? from rest_framework import status status = status. .....

that's a totally different word/question. At "value" level there's no difference, they both are 200 ... at "coding" level, as Charly said, one is a constant (that you should use instead) and the other is a direct numeric value

In general, which method is better to use?

No, it's better to use the constant

status =200 ?

No, read it again both our messages

What do you mean? The first returns only the value, the second return HTTP 200 OK ?

Both have the same value

So, do we use the second one to cleanly write the code?

Yes, read the link I sent

Well, you would have told me this earlier, anyway, thank you for your help

In general, which method is better to use?

I told you multiple times to read the messages

I've already said that in my message, didn't you read that?

I understood what I meant was the difference in the answer

I understood what I meant was the difference in the answer

The link is just additional info about why is better

I will read it soon

PLEASE I NEED HELP. I tried sending email via the gmail smtp server using send_mail(). The operation is SUCCESSFUL as indicated in the Python shell with a success code of "1", but the email is not delivered in the recipient email. Also, the email is not in the "Sent Mail" folder of the sender email. Yeah, I've checked the Spam/Junk folders of the recipient email, there's nothing there either. Any ideas what the problem is and possible solutions?

I used this site to start and test, take a look https://mailtrap.io

i think free for 100 emails but you can change your account 🙂

PLEASE I NEED HELP. I tried sending email via the gmail smtp server using send_mail(). The operation is SUCCESSFUL as indicated in the Python shell with a success code of "1", but the email is not delivered in the recipient email. Also, the email is not in the "Sent Mail" folder of the sender email. Yeah, I've checked the Spam/Junk folders of the recipient email, there's nothing there either. Any ideas what the problem is and possible solutions?

PLEASE I NEED HELP. I tried sending email via the gmail smtp server using send_mail(). The operation is SUCCESSFUL as indicated in the Python shell with a success code of "1", but the email is not delivered in the recipient email. Also, the email is not in the "Sent Mail" folder of the sender email. Yeah, I've checked the Spam/Junk folders of the recipient email, there's nothing there either. Any ideas what the problem is and possible solutions?

Send your code

# settings.py # Email Configuration EMAIL_BACKEND = 'django.core.mail.backends.smtp.EmailBackend' EMAIL_HOST = 'smtp.gmail.com' # Gmail's SMTP server EMAIL_PORT = 587 # The port for secure TLS connection EMAIL_USE_TLS = True # Use TLS (Transport Layer Security) to encrypt the connection EMAIL_HOST_USER = 'youremail@gmail.com' # Your Gmail email address EMAIL_HOST_PASSWORD = 'yourappspecificpassword' # App-specific password or your Gmail account password In the python shell: from django.core.mail import send_mail send_mail("Hello Friend", "Hello from Django", "myemail@gmail.com", ["clientemail@gmail.com"], fail_silently=False)

Do you have account in smtp.gmail.com?

I have a Gmail account. Isn't that the same thing?

Anyone knows any django-specific solution?

Please check that article.

Where did you host django project?

Not hosted yet, still on localhost

# settings.py # Email Configuration EMAIL_BACKEND = 'django.core.mail.backends.smtp.EmailBackend' EMAIL_HOST = 'smtp.gmail.com' # Gmail's SMTP server EMAIL_PORT = 587 # The port for secure TLS connection EMAIL_USE_TLS = True # Use TLS (Transport Layer Security) to encrypt the connection EMAIL_HOST_USER = 'youremail@gmail.com' # Your Gmail email address EMAIL_HOST_PASSWORD = 'yourappspecificpassword' # App-specific password or your Gmail account password In the python shell: from django.core.mail import send_mail send_mail("Hello Friend", "Hello from Django", "myemail@gmail.com", ["clientemail@gmail.com"], fail_silently=False)

I have a base.html file where I store the title line for the site. I also have a file for a different page I extend base.html to. My question is: how can I make a specific title for my page?

Might be you are writing the password of the gmail account that won't work here. First generate password through this youtube video and then use that in your project https://youtu.be/T0Op3Qzz6Ms?si=X5CeTnagKiWppQwG

add block in title part of base.html and define block content in your page file.

Thank you very much, I'm a newbie

So, did you solve issue?

I appreciate the comment, but I already did that. I Generated an app password from my Gmail account

Did anyone host ur django web app with sqlite on render if yes can u help me?

No one can help you until you explain your difficulties.

Or suggest me any free hosting service plzz

try pythonanywhere

Good afternoon, please tell me who may have faced an arbitrary stopping celery worker. Because of this I have situations where when I have a request 200 ok - I get an error log when there should be SUCCESS. At that, it is not for each tack, but on average, every 1.5 hours happens. From journalctl received such logs: окт 18 08:06:01 qsspchznrd celery[1645516]: [2023-10-18 11:06:01,185: ERROR/MainProcess] Process 'ForkPoolWorker-2' pid:1645519 exited with 'signal 15 (SIGTERM)' окт 18 08:06:01 qsspchznrd celery[1645516]: [2023-10-18 11:06:01,195: ERROR/MainProcess] Process 'ForkPoolWorker-1' pid:1645518 exited with 'signal 15 (SIGTERM)' That is, the process of the Worker was disabled. In the Django project put such a thing, so that there did not lose the task: CELERY_ACKS_LATE = True My celery tasks code: https://pastebin.com/KYix0PKZ My settings.py code: https://pastebin.com/hTmCpv9a As a result, falls into the common block except, which means that it is not a default python Exception, but some exit. Does anyone have any idea why celery is acting this way?

Maybe try provision additional resources for the celery tasks.

SIGTERM seems like it managed to terminate gracefully

You mean to increase concurrency setting inside the worker process?

Hi all. I have many applications, there are pictures and posts and news. I want to give them a like system. The best option I found is to make a separate application, make a model in it, and send requests via the REST API using JS FETCH. Are there better options? By the way, I still don’t know how to implement the model :)

Hi all. I have many applications, there are pictures and posts and news. I want to give them a like system. The best option I found is to make a separate application, make a model in it, and send requests via the REST API using JS FETCH. Are there better options? By the way, I still don’t know how to implement the model :)

Hi, there! Where i can use Django as a backend? Cuz backend developers make APIs for frontend and they use it. But i don't wanna use API? 😅

Like.... Basic using Templates (jinjer)

Like a frontend developer said that everything in backend is API