hello everyone. tell me. who knows... (a simplified version will be presented) class Tender(models.Model): product = models.ForeignKey(Product, on_delete=models.CASCADE) price = models.DecimalField(max_digits=4, decimal_places=2, default=0) class AddTenderForm(forms.ModelForm): class Meta: model = Tender fields = 'all now I want to write a form template from the model. and I know that you can do something like {{form.as_p }}, but I NEED to throw the product and price fields into different divas with different classes (template below) HOW DO I DO THIS? html for product <div class="col-12"> <label for="id_product" class="form-label">Product</label> <select class="form-select" name="product" id="id_product" required> <option value=""disabled selected></option> <option>{{ product }}</option> </select> <div class="invalid-feedback"> -- </div> html for price <div class="col-md-3"> <label for="id_price" class="form-label">Price</label> <input type="number" class="form-control" name="price" id="id_price" placeholder="Price" required> <div class="invalid-feedback"> -- </div> </div>

I need some resources to learn AJAX crud functionality

I need some resources to learn AJAX crud functionality

I removed the database and ran python manage.py runserver again.

yes i did still the same error

Hello, everyone. I need help regarding the django cron If anyone is familiar with it, Pls let me know setting.py file CRON_CLASSES = [ 'apps.utils.cron.add_team_quota_cron', ] apps/utils/cron.py class add_team_quota_cron(CronJobBase): schedule = Schedule(run_every_mins=1) # schedule = Schedule(run_at_times=['00:00'], monthly=1) code = 'add_team_quota' # a unique code def do(self): teams = Team.objects.filter(subscription_status=SubscriptionStatus.ACTIVE.value) for team in teams: create_team_quota(team, team.subscription_plan.id) when I run "python manage.py runcrons", cron job works only once... I think, the cron job doesn't work every minute

How do you proceed?

the issue is that when creating a super user, on arriving on the password prompt the console block suddenly. i did some researches and came about that it may be due to the hashing algorithm in the django setting but am not sure and the problem still persist

You can bypass the validation by typing y.

Hey guys My project structure like this: djrest/         api/         djrest/         products/ And i have a model in products.models called Product I wanna import the model in api.views But i get this error:     from ..products.models import Product ImportError: attempted relative import beyond top-level package And if i change it to: from djrest.products.models import Product I get : ModuleNotFoundError: no module named 'djrest.products' any solution guys?

Can anyone share a link to a Github repository with a good example of a Django project, preferably with user authentication implementation?

Try this from products.models import Product

https://bin.kv2.dev/~64907248e599576ea02cc70d

Hello i need help in django

Hi everyone I want to start learn django how can i start?

Hi everyone I want to start learn django how can i start?

Hello everybody, need help. I got such mistake "Could not find backend 'django.core.cache.backends.redis.RedisCache". Redis installed on ubuntu, django-redis installed in project, cache i wrote in settings. What should i do?

Django==3.2.12

my settings: CACHES = { 'default': { 'BACKEND': 'django.core.cache.backends.redis.RedisCache', 'LOCATION': 'redis://127.0.0.1:6379', 'OPTIONS': { 'CLIENT_CLASS': 'django.redis.client.DefaultClient' }, 'KEY_PREFIX': 'geekshop' } }

CACHES = { "default": { "BACKEND": "django_redis.cache.RedisCache", "LOCATION": "redis://127.0.0.1:6379/1", "OPTIONS": { "CLIENT_CLASS": "django_redis.client.DefaultClient", } } } something like this

now i got such thing : ModuleNotFoundError: No module named 'django.redis'

now i got such thing : ModuleNotFoundError: No module named 'django.redis'

django-redis installed correctly?

views.py: from django.shortcuts import render from .forms import StudentRegistration # Create your views here. class showformdata(request): fm = StudentRegistration() return render(request, 'enroll/userregistration.html', {'form':fm}) here i am getitng a syntaxError again and again the error is "return" outside function

views.py: from django.shortcuts import render from .forms import StudentRegistration # Create your views here. class showformdata(request): fm = StudentRegistration() return render(request, 'enroll/userregistration.html', {'form':fm}) here i am getitng a syntaxError again and again the error is "return" outside function

django-redis installed correctly?

also try change CLIENT_CLASS like in my message

please study Python first

@kataklizm88 look at this

thanks man, its working) i change ' into " in all settings and it works

👍 Its just because django use 'django.core.cache.backends.redis.RedisCache' from version 4. Up to version 4, django-redis is used. You probably opened the documentation for the 4th version and copied the settings from there.

Hey Everybody how are you? I Have a question about Django Rest Framework my question is now i have a project and two model that have a ManyToMany RelationShip together so I can create that in the restapi but I don't know when I send the data for this what should I send to Handle ManyToMany RelationShip here?

Hey Everybody how are you? I Have a question about Django Rest Framework my question is now i have a project and two model that have a ManyToMany RelationShip together so I can create that in the restapi but I don't know when I send the data for this what should I send to Handle ManyToMany RelationShip here?

Just like this. [1,2,3] Here 1 2 3 are id.

Just like this. [1,2,3] Here 1 2 3 are id.

can anyone who has been used render.com to host its Djago application on there? My images in the project has not being diplayed in there

Static files were deployed?

How?

hello `class Question(models.Model): question_title = models.CharField(verbose_name='question', max_length=255) created_at = models.DateTimeField(auto_now_add=True) updated_at = models.DateTimeField(auto_now=True) stage=models.ForeignKey('app.Stage', related_name = 'questions', on_delete=models.CASCADE) question_dependens_on_answer = models.ForeignKey('app.Answer', related_name = 'questions', blank=True,null=True, on_delete=models.CASCADE) question_type = models.CharField(max_length=50, blank=True, null=True) class Meta: verbose_name = 'Question' verbose_name_plural = 'Questions'` when i write qu = Question.objects.select_related('question_dependens_on_answer').all() this query django do LEFT OUTHER JOIN why?

because this field is nullable

Yess i find this answer thanks

views.py: from django.shortcuts import render from .forms import StudentRegistration # Create your views here. class showformdata(request): fm = StudentRegistration() return render(request, 'enroll/userregistration.html', {'form':fm}) here i am getitng a syntaxError again and again the error is "return" outside function