Did you modify your model and you are trying to makemigrations?

yes

Try to delete database file

You have file database.db in your project derectory

thankyou I do it and fixed

Hi guys. I am new in Django. Need your help. There is a one-to-many relationship. You must select all records that do not have records in the child table. On the fingers: there is a Parent model and a Child model: i wanna select all parents without children. A lot of thanks for your help in advance

You need to use filter and exclude method

Error Manager isn't available; 'auth.User' has been swapped for 'user.Profile'

Thanks for your answer. How can i exclude by child_set count?

Add your costumuser to the settings.py file

I don't really understand what you want to do but you can read about this in Django documentation search for making query

AUTH_USER_MODEL='yourapp.yourcostumuser'

in raw sql: SELECT * FROM Parents p LEFT JOIN Children c ON p.pk = c.parent_pk WHERE c.pk IS NULL

keypress tracking in django site. its realy ?

how to make tracking keys on the site.

I work with the site and I was wondering how to do it on the site

I can't find any info on this, I work with django and it makes it easy to validate anything.

Yeah. I want to spays

when you finished registration , you just need to hit the space bar and it will work like ok

def parent_without_children_view(request): parents_without_children = Parent.objects.select_related('children').filter(childrenpkisnull=True) context = { 'parents_without_children': parents_without_children } return render(request, 'parent_without_children.html', context)

children__isnull decided my problem. Thanks a lot!

Yes

Hello, why Django Channels is not suitable for real-time application? Does anyone have experience?

Hello, why Django Channels is not suitable for real-time application? Does anyone have experience?

Django Channels is not designed to handle high levels of concurrency, which can limit its ability to handle large volumes of traffic or multiple connections simultaneously.

Django Channels is not designed to handle high levels of concurrency, which can limit its ability to handle large volumes of traffic or multiple connections simultaneously.

Hey guys, I’m trying to create a web-shop and I need to have many images related to just one exact product. I tried with ManyToMany, but it’s hard to realise where is images, that I need, while adding them, can someone help pls?

I suggest this in barely Junior level questions, those who gave me them - tells that Middle level ones, who right? "What is the difference between Django's HttpResponse and JsonResponse classes? When would you use one over the other? What is Django's Object-Relational Mapping (ORM)? How does it work, and what are some advantages of using it? How do you use Django's built-in authentication system to handle user authentication and authorization? What is the difference between Django's STATIC_ROOT and STATICFILES_DIRS settings? How do you create a custom Django management command? What are some use cases for custom management commands?"

can anyone help i am getting this error:- " type error missing 1 required positional argument:id"

stackoverflow

I wanna use tether payment in my django project How i can?

use documentation

plz someone can help the apps are not able to run

Hello Team, I am new to Django and i need to learn it for my project. Can anyone suggest me the best course to learn and work on

https://learndjango.com/

Hello Team, I am new to Django and i need to learn it for my project. Can anyone suggest me the best course to learn and work on

https://stackoverflow.com/questions/75499413/set-declined-to-true-if-approved-is-false

Can anyone help me out with this

You have to update your model approved and declined doesn't make sense why have two fields when you can achieve same thing with only one remove those fields and add something like is_approved = models.BooleanField(default=False) And then make it True when it's approved

Reason why I have two fields is to be able to sort which request was approved and which was declined.

You can do that without creating two fields

How

Model_Name.objects.filter(is_approved=False)