it gave an error like this 'super' object has no attribute 'get_object'

it's kind of specific, i wanna do it with get but , I can't come yet

I know only one way of doing this don't take it serious and ask from others: 1. Go to urls and set up new path which will include 'somename/<field1>/<field2>/, YourViewName.as_view() 2. Get the object in your view with those fields and create it

hi guys. have you ever got in trouble with .heic photo format and django imagefield ? It seems django imagrfield does not support the .heic photo formating! have you any solotion?

try file field instead

Guys, need help. both functions are trying to change the same object. Works only the last one launched. How can i fix it? @transaction.atomic Def foo(pk): Obj=Object.objects.get(pk) Obj.foo += 1 Obj.save() @transaction.atomic Def bar(pk): Obj=Object.objects.get(pk) Obj.bar += 1 Obj.save()

Hello, what are the best versions of Django to start learning now? And are any versions backwards compatible?

Guys, need help. both functions are trying to change the same object. Works only the last one launched. How can i fix it? @transaction.atomic Def foo(pk): Obj=Object.objects.get(pk) Obj.foo += 1 Obj.save() @transaction.atomic Def bar(pk): Obj=Object.objects.get(pk) Obj.bar += 1 Obj.save()

There are several ways to avoid race conditions, 1. Try to use F functions obj.bar = F(‘bar’) + 1 obj.foo = F(‘foo’) + 1 2. Try to use update fields parameter when calling obj.save(update_fields=[‘foo’])

Well, Here's a code share(https://codeshare.io/ayvgRn) of the issue. I'll appreciate anyone who'll engage me on this.

read carefully https://t.me/django/198347

Apologies. I just sent the link here:https://t.me/django/198348

you did not do what is strongly recommended in the last line

Do you mean like in an array? No. It's because of how relational databases work - they return SETS. The only way is if you are sure that in a queryset you will get only specific number of records. Say we create a log record each hour, then for a day we could use indexes and etc.

{ "first_name": "string", "last_name": "string", "username": "anqov", "email": "user@example.com", "password": "string2", "password2": "string" } When posting above dictionary, Im getting default validation error: { "username": [ "A user with that username already exists." ] }

Thanks for your answer.. But how would it be possible to sort a SET, if i try to sort queryset using order_by method it would return a queryset with ordered object, what I'm trying to do is get index of single object without having to load all the queryset values.

Hi. I am trying to paginate my list in Django table without hitting database.

hi everyone I need help I want to delete recent actions in django admin panel where should I use this code in models.py or admin.py ....

Hi. I am trying to paginate my list in Django table without hitting database.

Can someone help me? How do I consume an external API with django to bring the data to the Front End?

You want to get data from a third party API within django? if yes, you can make requests with requests python library

> But how would it be possible to sort a SET From the theoretic perspective, a set not necessarily should be unsorted, like in python. It just can be not sorted. Sets only insure that you don't have repeated elements. > get index of single object without having to load all the queryset values. then just get that element. Simple as that.

I did but it didn't work because the headers are not released.

Well, you could cache the queryset somewhere so it doesn't hit DB. But honestly the question sounds like "I want to pump up my muscle, but don't want exercising."

def search(request): ids=[] if request.method == 'POST': text=request.POST.get('searchQuery') r1=Cheque.objects.filter(accountName__contains=text) r2=Cheque.objects.filter(chequeNumber__contains=text) r3=Cheque.objects.filter(chequeAmount__contains=text) for i in r1: ids.append(i) for j in r2: if j in ids: continue else: ids.append(j) for k in r3: if k in ids: continue else: ids.append(k) return render(request,'cheque/search.html',{'ids':ids})

def search(request): ids=[] if request.method == 'POST': text=request.POST.get('searchQuery') r1=Cheque.objects.filter(accountName__contains=text) r2=Cheque.objects.filter(chequeNumber__contains=text) r3=Cheque.objects.filter(chequeAmount__contains=text) for i in r1: ids.append(i) for j in r2: if j in ids: continue else: ids.append(j) for k in r3: if k in ids: continue else: ids.append(k) return render(request,'cheque/search.html',{'ids':ids})

what DB?

use QuerySet.values() method

I get 3 queryset. I want all the unique records from all three into one set. How can i do this ?

I get 3 queryset. I want all the unique records from all three into one set. How can i do this ?

def search(request): ids=[] if request.method == 'POST': text=request.POST.get('searchQuery') r1=Cheque.objects.filter(accountName__contains=text) r2=Cheque.objects.filter(chequeNumber__contains=text) r3=Cheque.objects.filter(chequeAmount__contains=text) for i in r1: ids.append(i) for j in r2: if j in ids: continue else: ids.append(j) for k in r3: if k in ids: continue else: ids.append(k) return render(request,'cheque/search.html',{'ids':ids})

def search(request): ids=[] if request.method == 'POST': text=request.POST.get('searchQuery') r1=Cheque.objects.filter(accountName__contains=text) r2=Cheque.objects.filter(chequeNumber__contains=text) r3=Cheque.objects.filter(chequeAmount__contains=text) for i in r1: ids.append(i) for j in r2: if j in ids: continue else: ids.append(j) for k in r3: if k in ids: continue else: ids.append(k) return render(request,'cheque/search.html',{'ids':ids})

But the custom field doesn't save into my model... can anyone enlighten me>

Yes. I am thinking to create the case if form is not valid.. I planned to do it after settling this genres custom field

in any case, use set instead of list

I have uploaded here https://dpaste.org/TPJ1

However, when I start up Django admin I have not a good display.