filter(username=’something’) filter(username__iexact=‘something’) ...read the docs

model.objects.filter(x=<some value>).values(...)

in case you have variable filter, you can use **kwargs and pass a dictionary

filter(username=’something’) filter(username__iexact=‘something’) ...read the docs

Got it

Thanks

Entry.objects.get(headline__contains='Lennon')

Entry.objects.get(headline__iexact='Lennon')

Entry.objects.get(headline__contains='Lennon')

%Lennon%

Entry.objects.get(headline__contains='Lennon')

this is better for single value search.

this is better for single value search.

How?

BTW __contains is case sensitive

for case insensitive, __icontains

.get(<some_filter>) == .filter().get() 🤔

.get(<some_filter>) == .filter().get() 🤔

.get() should return exactly 1 item Exception will be raised if there is none or more than 1 items

.get() should return exactly 1 item Exception will be raised if there is none or more than 1 items

that's correct

that’s my point

that’s my point

oh, the get()

Ah, right. I was just giving example of syntax. he can use it in filter as well.

Hi there, I am trying to config single sign in with iss with django. The negotiation happens, but I don't get the user back in response. Do you know how to do it?

https://dpaste.de/b2zR

https://dpaste.de/b2zR

Posts must return something

What should it return

What should it return

An httpresponse

An httpresponse

*response

Yeah

django rest framework does not obey: { 'NAME': 'django.contrib.auth.password_validation.MinimumLengthValidator' 'OPTIONS': { 'min_length': 6, } }?

as an option check the source code in your environment files, to check what parameters are accepted

The problem is this: register a new user in django admin with a password of 6 characters. More via api (django rest) validation requires a password of 8 characters.

Bizarre! Must obey my settings

are you no typos, or curly brackets fuckups ?

This should allow you to do 6 letter password in your admin panel and shell command

resolved!

what was it

hi can someone help me about (TemplateDoesNotExist at /api/ ) I still get this error when I try to launch my app

hi can someone help me about (TemplateDoesNotExist at /api/ ) I still get this error when I try to launch my app

by using django 2.0

urls.py

urls.py

And api views too

from django.urls import path from .views import PostPageView urlpatterns = [ path('',PostPageView.as_view(), name='posts'), ]

and the view

and the view

from django.shortcuts import render from django.views.generic import ListView from .models import Post # Create your views here. class PostPageView(ListView): model = Post template_name='template/posts.html'

template or templates?

"Templates"

error I wanted to write Templates But

It doesn't work

I don’t understand

Django by default looks for a templates folder not template Inside your app

Unless you defined a new template directory in settings

and called it template without the s

okay I see

let me try again

thanks I will try to find the solution

Templates/posts.html != template/posts.html

yeah sure

but I still get the same mistake

even if I change the name

just rename folder template to templates

it should be enough

I hope

your changing stuff and sending new photos

i’m lost

send your view class ur directory tree and your setting if you played with ur templates dictionary

is it about my post.html

I have classe called (post)

witch I have on column (text)

this is something else

First you need to find ur template

it's my settings.py

Stop sending screenshots or image files Use pastebin pls 🙏

Stop sending screenshots or image files Use pastebin pls 🙏

pastebin?

okay I see

pastebin?

Google it

duckduckgo 😂

already done

Whatever you want

But use it, it's easier for everyone to help you better

okay brother mine

My problem and return the url image in django. Ex: www.teste.com/media/name image

django rest.

have lib?

have lib?

no need other lib. only django-rest can handle.