Anonymous

You should to add a space at the end of string "concat"

.

thanks alot guys

many

C++ 11 onwards makes C++ like Java and C#

Abde

C++ 11 onwards makes C++ like Java and C#

what do you mean?

Anonymous

https://youtu.be/DK_0jXPuIr0

Anonymous

https://youtu.be/DK_0jXPuIr0

U

Hello guys!! i want to learn C , How should i start??

Anonymous

Sololearn.com

Secu

Sololearn.com

And practise

U

Thnx guyZ

Jay

Hello guys!! i want to learn C , How should i start??

I would suggest first get your hands on unix OS it will help a lot

Jay

Preferably virtual machine

Anonymous

morpheus: Guys Iam installing Windows 10 and updating it My question is Do I have to download drivers for my mother board , WiFi, etc Or Does the window 10 automatically download by itself?

Jay

morpheus: Guys Iam installing Windows 10 and updating it My question is Do I have to download drivers for my mother board , WiFi, etc Or Does the window 10 automatically download by itself?

It should 👍

U

morpheus: Guys Iam installing Windows 10 and updating it My question is Do I have to download drivers for my mother board , WiFi, etc Or Does the window 10 automatically download by itself?

Generally there's no need of drivers!!!

many

Macro vs function vs template, which is better in performance?

Evgenii

Macro vs function vs template, which is better in performance?

different things at all

Jay

We can have code challenge everyday here for easy category and read code one Solution is provided in details so new programmers can learn too. :)

Jay

Focusing on different aspects of C

Jay

Welcome new people :)

Anonymous

Hi

many

I'm currently playing with overloading subscripting operator (I.e. [ ]). I've tried to implement a class of safe array. The class checks if it's out of bound. The [ ] operator has to handle two scenarios, SafeArray arr(SIZE); arr[3] = 100; //arr[3] stores 100 int i = arr[3]; //load arr[3] to i How to handle these two scenarios when overloading [ ] operator?

many

Problem solved. Thx

many

The solution is returning as <type&>. returning with <type> can't handle arr[3]=100. returning with <type*> can't handle both scenarios

Jay

The solution is returning as <type&>. returning with <type> can't handle arr[3]=100. returning with <type*> can't handle both scenarios

👍

Anonymous

its about lvalue and rvalue

Anonymous

if we want change the return val, it should be lvalue

Anonymous